Svar 2.1:8
Förberedande kurs i matematik 1
(Skillnad mellan versioner)
(Ny sida: {| width="100%" cellspacing="10px" |a) |width="33%" | <math>\displaystyle \frac{x}{(x+3)(x+1)}</math> |b) |width="33%" | <math>\displaystyle \frac{2(x-3)}{x}</math> |c) |width="33%" | <mat...) |
(Ny sida: {| width="100%" cellspacing="10px" |a) |width="33%" | <math>\displaystyle \frac{x}{(x+3)(x+1)}</math> |b) |width="33%" | <math>\displaystyle \frac{2(x-3)}{x}</math> |c) |width="33%" | <mat...) |
Nuvarande version
a) | \displaystyle \displaystyle \frac{x}{(x+3)(x+1)} | b) | \displaystyle \displaystyle \frac{2(x-3)}{x} | c) | \displaystyle \displaystyle \frac{x+2}{2x+3} |