Svar 2.1:8

Förberedande kurs i matematik 1

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(Ny sida: {| width="100%" cellspacing="10px" |a) |width="33%" | <math>\displaystyle \frac{x}{(x+3)(x+1)}</math> |b) |width="33%" | <math>\displaystyle \frac{2(x-3)}{x}</math> |c) |width="33%" | <mat...)
Nuvarande version (31 mars 2008 kl. 12.10) (redigera) (ogör)
(Ny sida: {| width="100%" cellspacing="10px" |a) |width="33%" | <math>\displaystyle \frac{x}{(x+3)(x+1)}</math> |b) |width="33%" | <math>\displaystyle \frac{2(x-3)}{x}</math> |c) |width="33%" | <mat...)
 

Nuvarande version

a) \displaystyle \displaystyle \frac{x}{(x+3)(x+1)} b) \displaystyle \displaystyle \frac{2(x-3)}{x} c) \displaystyle \displaystyle \frac{x+2}{2x+3}