Svar 2.1:6
Förberedande kurs i matematik 1
(Skillnad mellan versioner)
(Ny sida: {| width="100%" cellspacing="10px" |a) |width="50%" | <math>2y</math> |b) |width="50%" | <math>\displaystyle\frac{-x+12}{(x-2)(x+3)}</math> |- |c) |width="50%" | <math>\displaystyle\frac{b...) |
(Ny sida: {| width="100%" cellspacing="10px" |a) |width="50%" | <math>2y</math> |b) |width="50%" | <math>\displaystyle\frac{-x+12}{(x-2)(x+3)}</math> |- |c) |width="50%" | <math>\displaystyle\frac{b...) |
Nuvarande version
| a) | \displaystyle 2y | b) | \displaystyle \displaystyle\frac{-x+12}{(x-2)(x+3)} |
| c) | \displaystyle \displaystyle\frac{b}{a(a-b)} | d) | \displaystyle \displaystyle\frac{a(a+b)}{4b} |
