Svar 4.1:5
Förberedande kurs i matematik 1
(Skillnad mellan versioner)
(Ny sida: {| width="100%" cellspacing="10px" |a) |width="100%" | <math>(x-1)^2+(y-2)^2=4</math> |- |b) |width="100%" | <math>(x-2)^2+(y+1)^2=13</math> |}) |
(Ny sida: {| width="100%" cellspacing="10px" |a) |width="100%" | <math>(x-1)^2+(y-2)^2=4</math> |- |b) |width="100%" | <math>(x-2)^2+(y+1)^2=13</math> |}) |
Nuvarande version
| a) | \displaystyle (x-1)^2+(y-2)^2=4 |
| b) | \displaystyle (x-2)^2+(y+1)^2=13 |
