Solution to Test Paper 2 - Revision history

Ian at 10:22, 8 April 2012

Ian — Sun, 08 Apr 2012 10:22:23 GMT

←Older revision		Revision as of 10:22, 8 April 2012
Line 1:		Line 1:
	{\| border="1"		{\| border="1"
	\|+ Solutions		\|+ Solutions
-
-
-	\|-
	\| 1 (a)		\| 1 (a)
	\| <math>\begin{align}		\| <math>\begin{align}
Line 334:		Line 331:
	\|		\|
	\| '''(8 marks)'''		\| '''(8 marks)'''
-	\|	+

Ian at 10:10, 8 April 2012

Ian — Sun, 08 Apr 2012 10:10:51 GMT

←Older revision		Revision as of 10:10, 8 April 2012
Line 130:		Line 130:
	& 800-900=2000a \\		& 800-900=2000a \\
	& a=\frac{-100}{2000}=-0\textrm{.}05 \text{ m}{{\text{s}}^{-2}} \\		& a=\frac{-100}{2000}=-0\textrm{.}05 \text{ m}{{\text{s}}^{-2}} \\
		+	& \text{Car is slowing down} \\
	\end{align}</math>		\end{align}</math>

-	~~Car is slowing down~~	+

Ian at 10:06, 8 April 2012

Ian — Sun, 08 Apr 2012 10:06:47 GMT

←Older revision		Revision as of 10:06, 8 April 2012
Line 6:		Line 6:
	\| 1 (a)		\| 1 (a)
	\| <math>\begin{align}		\| <math>\begin{align}
-	& 44 \ \textrm{.}1=\frac{1}{2}\times 9 \textrm{.} 8{{t}^{2}} \\	+	& 44\textrm{.}1=\frac{1}{2}\times 9\textrm{.}8{{t}^{2}} \\
-	& t=\sqrt{\frac{44 \textrm{.}1}{4 \textrm{.}9}}=3\text{ s} \\	+	& t=\sqrt{\frac{44\textrm{.}1}{4\textrm{.}9}}=3\text{ s} \\
-	\~~end{align}</math>~~	+	& \\
-		+	& \text{OR} \\
-	OR	+	& \\
-		+	& s=\frac{1}{2}\times 9\textrm{.}8\times {{3}^{2}}=44\textrm{.}1 \\
-	~~<math>~~\~~begin~~{~~align~~}	+
-	& s=\frac{1}{2}\times 9 \textrm{.}8\times {{3}^{2}}=44 \textrm{.}1 \\	+
-	~~& \text{AG}~~ \\	+
	& \therefore \text{Hits ground after 3 seconds} \\		& \therefore \text{Hits ground after 3 seconds} \\
	\end{align}</math>		\end{align}</math>

-		+	AG


Line 49:		Line 46:
	\| 1 (b)		\| 1 (b)
	\| <math>\begin{align}		\| <math>\begin{align}
-	& {{v}^{2}}={{0}^{2}}+2\times 9 \textrm{.}8\times 44 \textrm{.}1 \\	+	& {{v}^{2}}={{0}^{2}}+2\times 9\textrm{.}8\times 44\textrm{.}1 \\
-	& v=\sqrt{864 \textrm{.}36}=29 \ \textrm{.}4\text{ m}{{\~~text~~{s}}^{-1}} \\	+	& v=\sqrt{864\textrm{.}36}=29\textrm{.}4m \\
		+	& \\
		+	& \text{OR} \\
		+	& \\
		+	& v=0+9\textrm{.}8\times 3 \\
		+	& v=29\textrm{.}4 \\
	\end{align}</math>		\end{align}</math>

-	OR
-
-	<math>\begin{align}
-	& v=0+9 \textrm{.}8\times 3 \\
-	& v=29 \textrm{.}4 \text{ m}{{\text{s}}^{-1}} \\
-	\end{align}</math>

Ian at 16:43, 19 January 2011

Ian — Wed, 19 Jan 2011 16:43:20 GMT

←Older revision		Revision as of 16:43, 19 January 2011
Line 269:		Line 269:

	\|-		\|-
-	\| 1	+	\|
-	\| 2	+	\|
-	\| 3	+	\|
-	\| 4	+	\| '''(8 marks)'''
-	\| 5	+	\|

	\|-		\|-
	\| 5 (a)		\| 5 (a)
-	\| 2	+	\| <math>\mathbf{v}=(6\mathbf{i}+4\mathbf{j})+(0\textrm{.}2\mathbf{i}-0\textrm{.}4\mathbf{j})t</math>
-	\| 3	+	\| M1
-	\| 4	+
-	\| 5	+	A1
		+	\| (2 marks)
		+	\| M1: Use of <math>\mathbf{v}=\mathbf{u}+\mathbf{a}t</math>
		+
		+	A1: Correct expression
		+

	\|-		\|-
	\| 5 (b)		\| 5 (b)
-	\| 2	+	\| <math>\begin{align}
-	\| 3	+	& 4-0\textrm{.}4t=0 \\
-	\| 4	+	& t=10 \ \text{s}\\
-	\| 5	+	\end{align}</math>
		+
		+	\| M1
		+
		+	A1
		+
		+	A1
		+
		+	\| (3 marks)
		+	\| M1: Using <math>\mathbf{j}</math> component equal to zero.
		+
		+	A1: Correct equation.
		+
		+	A1: Correct time.
		+
	\|-		\|-
	\| 5 (c)		\| 5 (c)
-	\| 2	+	\| <math>\begin{align}
-	\| 3	+	& \mathbf{r}=(6\mathbf{i}+4\mathbf{j})\times 30+\frac{1}{2}(0\textrm{.}2\mathbf{i}-0\textrm{.}4\mathbf{j})\times {{30}^{2}} \\
-	\| 4	+	& =270\mathbf{i}-60\mathbf{j} \\
-	\| 5	+	& r=\sqrt{{{270}^{2}}+{{60}^{2}}}=277\ \text{m} \\
		+	\end{align}</math>
		+
		+	\| M1
		+
		+	A1
		+
		+	M1
		+
		+	A1
		+
		+	\| (4 marks)
		+	\| M1: Using <math>\mathbf{r}=\mathbf{u}t+\frac{1}{2}\mathbf{a}{{t}^{2}}</math>
		+
		+	A1: Correct position vector.
		+
		+	M1: Finding distance.
		+
		+	A1: Correct distance
		+
		+	\|-
		+	\|
		+	\|
		+	\|
		+	\| '''(8 marks)'''
		+	\|


	\|}		\|}
		+
		+	KEY
		+	M1: Method Mark
		+
		+	A1: Accuracy Mark following a method mark
		+
		+	B1: Accuracy Mark not following a method mark
		+
		+	AG: Answer Given in Question – Working must justify answer.
		+
		+	TOTAL: '''40 Marks'''

Ian at 16:22, 19 January 2011

Ian — Wed, 19 Jan 2011 16:22:38 GMT

←Older revision		Revision as of 16:22, 19 January 2011
Line 219:		Line 219:
	\| 4 (a)		\| 4 (a)
	\| [[Image:test2ans4.gif]]		\| [[Image:test2ans4.gif]]
-	\| 3	+	\| B1
-	\| 4	+	\| (1 mark)
-	\| 5	+	\| B1: Correct force diagram

	\|-		\|-
	\| 4 (b)		\| 4 (b)
-	\| 2	+	\| <math>\begin{align}
-	\| 3	+	& 100a=200-980\sin 5{}^\circ \\
-	\| 4	+	& a=\frac{200-980\sin 5{}^\circ }{100}=1\textrm{.}15\ \text{m}{{\text{s}}^{-2}} \\
-	\| 5	+	\end{align}</math>
		+
		+	\| M1A1
		+
		+	M1
		+
		+	A1
		+
		+	\| (4 marks)
		+	\| M1: Three term equation of motion
		+
		+	A1: Correct equation
		+
		+	M1: Rearranging equation.
		+
		+	A1: Correct <math>a</math>.
		+

	\|-		\|-
	\| 4 (c)		\| 4 (c)
-	\| 2	+	\|
-	\| 3	+	<math>\begin{align}
-	\| 4	+	& s=0\times 5+\frac{1}{2}\times 1\textrm{.}15\times {{5}^{2}} \\
-	\| 5	+	& =14\textrm{.}4\ \text{m} \\
		+	\end{align}</math>
		+
		+	\| M1
		+
		+	A1
		+
		+	A1
		+
		+	\| (3 marks)
		+	\| M1: Using a constant acceleration equation
		+
		+	A1: Correct equation
		+
		+	A1: Correct distance.
		+

	\|-		\|-

Ian at 15:59, 19 January 2011

Ian — Wed, 19 Jan 2011 15:59:48 GMT

←Older revision		Revision as of 15:59, 19 January 2011
Line 6:		Line 6:
	\| 1 (a)		\| 1 (a)
	\| <math>\begin{align}		\| <math>\begin{align}
-	& 44 \ \textrm{.}1=\frac{1}{2}\times 9 \ \ 8{{t}^{2}} \\	+	& 44 \ \textrm{.}1=\frac{1}{2}\times 9 \textrm{.} 8{{t}^{2}} \\
	& t=\sqrt{\frac{44 \textrm{.}1}{4 \textrm{.}9}}=3\text{ s} \\		& t=\sqrt{\frac{44 \textrm{.}1}{4 \textrm{.}9}}=3\text{ s} \\
	\end{align}</math>		\end{align}</math>
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	\|-		\|-
	\| 4 (a)		\| 4 (a)
-	\| 2	+	\| [[Image:test2ans4.gif]]
	\| 3		\| 3
	\| 4		\| 4

Ian at 15:49, 19 January 2011

Ian — Wed, 19 Jan 2011 15:49:10 GMT

←Older revision		Revision as of 15:49, 19 January 2011
Line 178:		Line 178:
	\|-		\|-
	\| 3 (b)		\| 3 (b)
-	\| <math>F=0\textrm{.}4\times 196=78\textrm{.}4</math>	+	\| <math>F=0\textrm{.}4\times 196=78\textrm{.}4</math> N
	\| M1		\| M1

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	\|-		\|-
	\| 3 (c)		\| 3 (c)
-	\| 2	+	\| <math>\begin{align}
-	\| 3	+	& 100-78 \textrm{.}4=20a \\
-	\| 4	+	& a=\frac{100-78 \textrm{.}4}{20}=1 \textrm{.}08 \text{ m}{{\text{s}}^{-2}} \\
-	\| 5	+	\end{align}</math>
		+
		+	\| M1
		+
		+	A1
		+
		+	A1
		+
		+	\| (3 marks)
		+	\| M1: Three term equation of motion
		+
		+	A1: Correct equation
		+
		+	A1: Correct <math>a</math>.
		+

	\|-		\|-
-	\| 1	+	\|
-	\| 2	+	\|
-	\| 3	+	\|
-	\| 4	+	\| '''(8 marks)'''
-	\| 5	+	\|

	\|-		\|-

Ian at 15:35, 19 January 2011

Ian — Wed, 19 Jan 2011 15:35:41 GMT

←Older revision		Revision as of 15:35, 19 January 2011
Line 165:		Line 165:
	\|-		\|-
	\| 3 (a)		\| 3 (a)
-	\| 2	+	\| <math>R=20\times 9\textrm{.}8=196</math> N
-	\| 3	+	\|M1
-	\| 4	+
-	\| 5	+	A1
		+
		+	\| (2 marks)
		+	\| M1: Use of <math>R=mg</math>
		+
		+	A1: Correct <math>R</math>.
		+

	\|-		\|-
	\| 3 (b)		\| 3 (b)
-	\| 2	+	\| <math>F=0\textrm{.}4\times 196=78\textrm{.}4</math>
-	\| 3	+	\| M1
-	\| 4	+
-	\| 5	+	A1
		+	\| (2 Marks)
		+	\| M1: Use of <math>F=\mu R</math>
		+
		+	A1: Correct <math>F</math>.
		+

	\|-		\|-

Ian at 15:00, 19 January 2011

Ian — Wed, 19 Jan 2011 15:00:32 GMT

←Older revision		Revision as of 15:00, 19 January 2011
Line 86:		Line 86:

	\|-		\|-
-	\| 1	+	\|
-	\| 2	+	\|
-	\| 3	+	\|
-	\| 4	+	\| '''(7 marks)'''
-	\| 5	+	\|

	\|-		\|-
	\| 2 (a)		\| 2 (a)
-	\| 2	+	\| [[Image:test2ans2.gif]]
-	\| 3	+	\| B1
-	\| 4	+	\| (1 mark)
-	\| 5	+	\| B1: Correct horizontal forces.
		+	Ignore any vertical forces.
		+

	\|-		\|-
	\| 2 (b)		\| 2 (b)
-	\| 2	+	\| <math>P = 900 \text{N}</math>
-	\| 3	+	\| B1
-	\| 4	+	\| (1 mark)
-	\| 5	+	\| B1: Correct value for <math>P</math>.

	\|-		\|-
	\| 2 (c)		\| 2 (c)
-	\| 2	+	\| <math>\begin{align}
-	\| 3	+	& P-900=2000\times 1\textrm{.}2 \\
-	\| 4	+	& P=2400+900=3300 \text{N} \\
-	\| 5	+	\end{align}</math>
		+
		+	\| M1
		+
		+	A1
		+
		+	A1
		+
		+	\| (1 mark)
		+	\| M1: Three term equation of motion
		+
		+	A1: Correct equation
		+
		+	A1: Correct <math>P</math>.
		+

	\|-		\|-
	\| 2 (d)		\| 2 (d)
-	\| 2	+	\| <math>\begin{align}
-	\| 3	+	& 800-900=2000a \\
-	\| 4	+	& a=\frac{-100}{2000}=-0\textrm{.}05 \text{ m}{{\text{s}}^{-2}} \\
-	\| 5	+	\end{align}</math>
		+
		+	Car is slowing down
		+
		+
		+	\| M1
		+
		+	A1
		+
		+	A1
		+
		+	A1
		+
		+	\| (4 marks)
		+	\| M1: Three term equation of motion
		+	A1: Correct equation
		+
		+	A1: Correct <math>a</math>
		+
		+	A1: Correct statement
		+

	\|-		\|-
-	\| 1	+	\|
-	\| 2	+	\|
-	\| 3	+	\|
-	\| 4\| 5	+	\| '''(9 marks)'''
		+	\|
		+
	\|-		\|-
	\| 3 (a)		\| 3 (a)

Ian at 14:13, 19 January 2011

Ian — Wed, 19 Jan 2011 14:13:59 GMT

←Older revision		Revision as of 14:13, 19 January 2011
Line 6:		Line 6:
	\| 1 (a)		\| 1 (a)
	\| <math>\begin{align}		\| <math>\begin{align}
-	& 44.1=\frac{1}{2}\times 9.8{{t}^{2}} \\	+	& 44 \ \textrm{.}1=\frac{1}{2}\times 9 \ \ 8{{t}^{2}} \\
-	& t=\sqrt{\frac{44.1}{4.9}}=3\text{ s} \\	+	& t=\sqrt{\frac{44 \textrm{.}1}{4 \textrm{.}9}}=3\text{ s} \\
	\end{align}</math>		\end{align}</math>

Line 13:		Line 13:

	<math>\begin{align}		<math>\begin{align}
-	& s=\frac{1}{2}\times 9.8\times {{3}^{2}}=44.1 \\	+	& s=\frac{1}{2}\times 9 \textrm{.}8\times {{3}^{2}}=44 \textrm{.}1 \\
	& \text{AG} \\		& \text{AG} \\
	& \therefore \text{Hits ground after 3 seconds} \\		& \therefore \text{Hits ground after 3 seconds} \\
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	\|-		\|-
	\| 1 (b)		\| 1 (b)
-	\| 2	+	\| <math>\begin{align}
-	\| 3	+	& {{v}^{2}}={{0}^{2}}+2\times 9 \textrm{.}8\times 44 \textrm{.}1 \\
-	\| 4	+	& v=\sqrt{864 \textrm{.}36}=29 \ \textrm{.}4\text{ m}{{\text{s}}^{-1}} \\
		+	\end{align}</math>
		+
		+	OR
		+
		+	<math>\begin{align}
		+	& v=0+9 \textrm{.}8\times 3 \\
		+	& v=29 \textrm{.}4 \text{ m}{{\text{s}}^{-1}} \\
		+	\end{align}</math>
		+
		+
		+	\|M1
		+
		+	A1
		+
		+	A1
		+
		+
		+	\| (3 marks)
		+
		+
		+	\| M1: Use of constant acceleration equation with <math>v=0</math>
		+
		+	A1: Correct equation.
		+
		+	A1: Correct <math>v</math>.
		+

	\|-		\|-
	\| 1 (c)		\| 1 (c)
-	\| 2	+	\| Air resistance would slow the ball down.
-	\| 3	+	\| B1
-	\| 4	+	\| (1 mark)
		+	\| B1: Sensible statement about air resistance.

	\|-		\|-
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	\| 3		\| 3
	\| 4		\| 4
		+	\| 5

	\|-		\|-
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	\| 3		\| 3
	\| 4		\| 4
		+	\| 5

	\|-		\|-
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	\| 3		\| 3
	\| 4		\| 4
		+	\| 5

	\|-		\|-
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	\| 3		\| 3
	\| 4		\| 4
		+	\| 5

	\|-		\|-
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	\| 3		\| 3
	\| 4		\| 4
		+	\| 5

	\|-		\|-
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	\| 2		\| 2
	\| 3		\| 3
-	\| 4	+	\| 4\| 5
-		+
	\|-		\|-
	\| 3 (a)		\| 3 (a)
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	\| 3		\| 3
	\| 4		\| 4
		+	\| 5

	\|-		\|-
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	\| 3		\| 3
	\| 4		\| 4
		+	\| 5

	\|-		\|-
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	\| 3		\| 3
	\| 4		\| 4
		+	\| 5

	\|-		\|-
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	\| 3		\| 3
	\| 4		\| 4
		+	\| 5

	\|-		\|-
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	\| 3		\| 3
	\| 4		\| 4
		+	\| 5

	\|-		\|-
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	\| 3		\| 3
	\| 4		\| 4
		+	\| 5

	\|-		\|-
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	\| 3		\| 3
	\| 4		\| 4
		+	\| 5

	\|-		\|-
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	\| 3		\| 3
	\| 4		\| 4
		+	\| 5

	\|-		\|-
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	\| 3		\| 3
	\| 4		\| 4
		+	\| 5

	\|-		\|-
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	\| 3		\| 3
	\| 4		\| 4
-		+	\| 5
	\|-		\|-
	\| 5 (c)		\| 5 (c)
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	\| 3		\| 3
	\| 4		\| 4
-		+	\| 5


	\|}		\|}