Ian at 18:03, 16 May 2010

Ian — Sun, 16 May 2010 18:03:30 GMT

←Older revision		Revision as of 18:03, 16 May 2010
Line 2:		Line 2:

	Resolving horisontally,		Resolving horisontally,
-

	<math>\begin{align}		<math>\begin{align}
-	& \to :\quad 42+P-Q\cos {{45}^{\circ }}=0 \\	+	& \to :\quad 42\cos {{30}^{\circ }}+P-Q\cos {{45}^{\circ }}=0 \\
	& \\		& \\
	\end{align}</math>		\end{align}</math>

	Resolving vertically,		Resolving vertically,
-

	<math>\begin{align}		<math>\begin{align}
Line 17:		Line 15:
	& Q=\frac{25+42\sin {{30}^{\circ }}}{\cos {{45}^{\circ }}}=\frac{46}{0\textrm{.}707}=65\textrm{.}1 \ \text{N} \\		& Q=\frac{25+42\sin {{30}^{\circ }}}{\cos {{45}^{\circ }}}=\frac{46}{0\textrm{.}707}=65\textrm{.}1 \ \text{N} \\
	\end{align}</math>		\end{align}</math>
		+
		+	Substituting this value for <math>Q</math> in the first equation gives
		+
		+	<math>P=Q\cos {{45}^{\circ }}-42\cos {{30}^{\circ }}=65\textrm{.}1\times 0\textrm{.}707-42\times 0\textrm{.}866=46-36\textrm{.}4=9\textrm{.}6\ \text{N}</math>

Ian: New page: The sum of the forces is zero as the body has constant velocity. This means the sum of the forces in all directions is zero. Resolving horisontally, $\begin{align} & \to :\quad 42+...$

Ian — Sun, 16 May 2010 17:41:11 GMT

New page: The sum of the forces is zero as the body has constant velocity. This means the sum of the forces in all directions is zero. Resolving horisontally, <math>\begin{align} & \to :\quad 42+...

New page

The sum of the forces is zero as the body has constant velocity. This means the sum of the forces in all directions is zero.

Resolving horisontally,

<math>\begin{align}
& \to :\quad 42+P-Q\cos {{45}^{\circ }}=0 \\
& \\
\end{align}</math>

Resolving vertically,

<math>\begin{align}
& \uparrow :\quad 25+42\sin {{30}^{\circ }}-Q\cos {{45}^{\circ }}=0 \\
& \\
& Q=\frac{25+42\sin {{30}^{\circ }}}{\cos {{45}^{\circ }}}=\frac{46}{0\textrm{.}707}=65\textrm{.}1 \ \text{N} \\
\end{align}</math>

Solution 9.2c - Revision history

Ian at 18:03, 16 May 2010

Ian: New page: The sum of the forces is zero as the body has constant velocity. This means the sum of the forces in all directions is zero. Resolving horisontally, \begin{align} & \to :\quad 42+...

Ian: New page: The sum of the forces is zero as the body has constant velocity. This means the sum of the forces in all directions is zero. Resolving horisontally, $\begin{align} & \to :\quad 42+...$