Ian: New page: The sum of the forces is zero as the body has constant velocity. This means the sum of the forces in all directions is zero. Resolving horisontally, $\begin{align} & \to :\quad 42\c...$

Ian — Sun, 16 May 2010 17:25:48 GMT

New page: The sum of the forces is zero as the body has constant velocity. This means the sum of the forces in all directions is zero. Resolving horisontally, <math>\begin{align} & \to :\quad 42\c...

New page

The sum of the forces is zero as the body has constant velocity. This means the sum of the forces in all directions is zero.

Resolving horisontally,

<math>\begin{align}
& \to :\quad 42\cos {{30}^{\circ }}-P=0 \\
& \\
& P=42\cos {{30}^{\circ }}=36\textrm{.}4\ \text{N} \\
\end{align}</math>

Resolving vertically,

<math>\begin{align}
& \uparrow :\quad 25+42\times \sin {{30}^{\circ }}-Q=0 \\
& \\
& Q=25+21=46\ \text{N} \\
\end{align}</math>

Solution 9.2b - Revision history

Ian: New page: The sum of the forces is zero as the body has constant velocity. This means the sum of the forces in all directions is zero. Resolving horisontally, \begin{align} & \to :\quad 42\c...

Ian: New page: The sum of the forces is zero as the body has constant velocity. This means the sum of the forces in all directions is zero. Resolving horisontally, $\begin{align} & \to :\quad 42\c...$