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		<title>Solution 9.1 - Revision history</title>
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			<title>Ian: New page: Image:9.1.gif  As the parachutist is falling vertically (in other words in a straight line) and at constant speed, her velocity is constant. This means the forces acting on her must ha...</title>
			<link>http://wiki.sommarmatte.se/wikis/2009/bridgecoursemechanics/index.php?title=Solution_9.1&amp;diff=1120&amp;oldid=prev</link>
			<description>&lt;p&gt;New page: &lt;a href=&quot;/wikis/2009/bridgecoursemechanics/index.php/Image:9.1.gif&quot; title=&quot;Image:9.1.gif&quot;&gt;Image:9.1.gif&lt;/a&gt;  As the parachutist is falling vertically (in other words in a straight line) and at constant speed, her velocity is constant. This means the forces acting on her must ha...&lt;/p&gt;
&lt;p&gt;&lt;b&gt;New page&lt;/b&gt;&lt;/p&gt;&lt;div&gt;[[Image:9.1.gif]]&lt;br /&gt;
&lt;br /&gt;
As the parachutist is falling vertically (in other words in a straight line) and at constant speed, her velocity is constant. This means the forces acting on her must have zero sum.&lt;br /&gt;
&lt;br /&gt;
Taking upwards as positive,&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;\uparrow :\quad F-mg=0&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;F=mg=80\times 9\textrm{.}8=784\ \text{N}&amp;lt;/math&amp;gt;&lt;/div&gt;</description>
			<pubDate>Sun, 16 May 2010 16:09:28 GMT</pubDate>			<dc:creator>Ian</dc:creator>			<comments>http://wiki.sommarmatte.se/wikis/2009/bridgecoursemechanics/index.php/Talk:Solution_9.1</comments>		</item>
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