Ian at 15:40, 19 April 2010

Ian — Mon, 19 Apr 2010 15:40:37 GMT

←Older revision		Revision as of 15:40, 19 April 2010
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-	We use <math>\mathbf{v}=\mathbf{u}+\mathbf{a}t</math> with	+	We use <math>\mathbf{v}=\mathbf{u}+\mathbf{a}t \ </math> with

	<math>\mathbf{u}=15\mathbf{i}+18\mathbf{j}\text{ m}{{\text{s}}^{\text{-1}}}</math>		<math>\mathbf{u}=15\mathbf{i}+18\mathbf{j}\text{ m}{{\text{s}}^{\text{-1}}}</math>
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	Simplifying <math>\mathbf{v}=15\mathbf{i}+18\mathbf{j}-30\mathbf{j}=15\mathbf{i}-12\mathbf{j} </math>		Simplifying <math>\mathbf{v}=15\mathbf{i}+18\mathbf{j}-30\mathbf{j}=15\mathbf{i}-12\mathbf{j} </math>
		+
		+	The speed <math>S</math> is the magnitude of this velocity.
		+
		+	<math>S=\sqrt{{{15}^{2}}+{{\left( -12 \right)}^{2}}}=\sqrt{225+144}=19\textrm{.}2\ \text{m}{{\text{s}}^{-1}}</math>

Ian: New page: We use $\mathbf{v}=\mathbf{u}+\mathbf{a}t$ with $\mathbf{u}=15\mathbf{i}+18\mathbf{j}\text{ m}{{\text{s}}^{\text{-1}}}$ $\mathbf{a}=-10\mathbf{j}$
Ian — Mon, 19 Apr 2010 15:26:53 GMT

New page: We use <math>\mathbf{v}=\mathbf{u}+\mathbf{a}t</math> with <math>\mathbf{u}=15\mathbf{i}+18\mathbf{j}\text{ m}{{\text{s}}^{\text{-1}}}</math> <math>\mathbf{a}=-10\mathbf{j}</math> <math...

New page
We use <math>\mathbf{v}=\mathbf{u}+\mathbf{a}t</math> with

<math>\mathbf{u}=15\mathbf{i}+18\mathbf{j}\text{ m}{{\text{s}}^{\text{-1}}}</math>

<math>\mathbf{a}=-10\mathbf{j}</math>

<math>t=3\text{ s}</math>

giving <math>\mathbf{v}=15\mathbf{i}+18\mathbf{j}+(-10\mathbf{j} )\times 3</math>

Simplifying <math>\mathbf{v}=15\mathbf{i}+18\mathbf{j}-30\mathbf{j}=15\mathbf{i}-12\mathbf{j} </math>