Ian at 19:04, 14 April 2010

Ian — Wed, 14 Apr 2010 19:04:02 GMT

←Older revision		Revision as of 19:04, 14 April 2010
Line 4:		Line 4:
	Also		Also

-	<math>\mathbf{v}=\mathbf{u}+\mathbf{a}t</math> gives,	+	<math>\mathbf{v}=\mathbf{u}+\mathbf{a}t\ </math> gives,

	<math>6\mathbf{i}-8\mathbf{j}=\mathbf{i}+2\mathbf{j}+\mathbf{a} \times 10</math>		<math>6\mathbf{i}-8\mathbf{j}=\mathbf{i}+2\mathbf{j}+\mathbf{a} \times 10</math>

Ian: New page: $\mathbf{u}=\mathbf{i}+2\mathbf{j}$ and $\mathbf{v}= 6\mathbf{i}-8\mathbf{j}$ when $t=10$ . Also $\mathbf{v}=\mathbf{u}+\mathbf{a}t$ gives, <...

Ian — Wed, 14 Apr 2010 19:02:45 GMT

New page: <math>\mathbf{u}=\mathbf{i}+2\mathbf{j}</math> and <math>\mathbf{v}= 6\mathbf{i}-8\mathbf{j}</math> when <math>t=10</math>. Also <math>\mathbf{v}=\mathbf{u}+\mathbf{a}t</math> gives, <...

New page

<math>\mathbf{u}=\mathbf{i}+2\mathbf{j}</math> and <math>\mathbf{v}=
6\mathbf{i}-8\mathbf{j}</math> when <math>t=10</math>.

Also

<math>\mathbf{v}=\mathbf{u}+\mathbf{a}t</math> gives,

<math>6\mathbf{i}-8\mathbf{j}=\mathbf{i}+2\mathbf{j}+\mathbf{a} \times 10</math>

<math>10\mathbf{a}=6\mathbf{i}-8\mathbf{j}-\mathbf{i}-2\mathbf{j}=5\mathbf{i}-10\mathbf{j}</math>

<math>\mathbf{a}=0\textrm{.}5\mathbf{i}-\mathbf{j}\ \text{m}{{\text{s}}^{-2}}</math>

Solution 8.6a - Revision history

Ian at 19:04, 14 April 2010

Ian: New page: \mathbf{u}=\mathbf{i}+2\mathbf{j} and \mathbf{v}= 6\mathbf{i}-8\mathbf{j} when t=10. Also \mathbf{v}=\mathbf{u}+\mathbf{a}t gives, <...

Ian: New page: $\mathbf{u}=\mathbf{i}+2\mathbf{j}$ and $\mathbf{v}= 6\mathbf{i}-8\mathbf{j}$ when $t=10$ . Also $\mathbf{v}=\mathbf{u}+\mathbf{a}t$ gives, <...