Solution 8.4c - Revision history

Ian at 16:48, 13 April 2010

Ian — Tue, 13 Apr 2010 16:48:25 GMT

←Older revision		Revision as of 16:48, 13 April 2010
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	Substituting the above values gives a vector equation for <math>t</math>.		Substituting the above values gives a vector equation for <math>t</math>.

-	<math>4\textrm{.}8\mathbf{i}-6\textrm{.}8\mathbf{j}=0\~~textrm~~{.}2\mathbf{i}+0\textrm{.}3\mathbf{j}+(4\~~mathbf~~{i}~~– 8~~\mathbf{j})t\ \</math>	+	<math>4\textrm{.}8\mathbf{i}-6\textrm{.}8\mathbf{j}=4\mathbf{i}-8\mathbf{j}+(0\textrm{.}2\mathbf{i}+0\textrm{.}3\mathbf{j})t\ \</math>

-	0r <math>4\textrm{.}8\mathbf{i}-6\textrm{.}8\mathbf{j}=(4t+0\textrm{.}2\ )\mathbf{i}– (8t+0\textrm{.}3\ )\mathbf{j}\ \</math>	+	0r <math>4\textrm{.}8\mathbf{i}-6\textrm{.}8\mathbf{j}=(4+0\textrm{.}2t\ )\mathbf{i}+ (0\textrm{.}3t-8\ )\mathbf{j}\ \</math>
		+
		+	Is there a <math>t</math> which satisfies both the <math>\mathbf{i}</math> terms and the <math>\mathbf{j}</math> terms?
		+
		+	<math>4\textrm{.}8\mathbf{i}=(4+0\textrm{.}2t\ )\mathbf{i}\ \</math>
		+
		+	and
		+
		+	<math>-6\textrm{.}8\mathbf{j}=(0\textrm{.}3t-8\ )\mathbf{j}\ \</math>
		+
		+	It is easily seen that <math>t=4 \ \text{s}</math> satisfies both these equations.

Ian at 16:38, 13 April 2010

Ian — Tue, 13 Apr 2010 16:38:43 GMT

←Older revision		Revision as of 16:38, 13 April 2010
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-	We have <math>\mathbf{a}=4\mathbf{i}~~– 8~~\mathbf{j},\ \</math> <math>\mathbf{u}=4\mathbf{i}– 8\mathbf{j}\ \</math> and <math>\ \ \mathbf{ r}_{0}=6\mathbf{i}+2\mathbf{j}</math>.	+	We have <math>\mathbf{a}=0\textrm{.}2\mathbf{i}+0\textrm{.}3\mathbf{j},\ \</math> <math>\mathbf{u}=4\mathbf{i}– 8\mathbf{j}\ \</math> and <math>\ \ \mathbf{ r}_{0}=6\mathbf{i}+2\mathbf{j}</math>.

	The most suitable equation to use is <math>\mathbf{v}=\mathbf{u}+\mathbf{a}t\ \</math>.		The most suitable equation to use is <math>\mathbf{v}=\mathbf{u}+\mathbf{a}t\ \</math>.

-	Substituting the above values gives a vector ~~eqaution~~ for <math>t</math>.	+	Substituting the above values gives a vector equation for <math>t</math>.

-	<math>4\textrm{.}8\mathbf{i}-6\textrm{.}8\mathbf{j}=4\mathbf{i}~~– 8~~\mathbf{j}+(4\mathbf{i}– 8\mathbf{j})t\ \</math>	+	<math>4\textrm{.}8\mathbf{i}-6\textrm{.}8\mathbf{j}=0\textrm{.}2\mathbf{i}+0\textrm{.}3\mathbf{j}+(4\mathbf{i}– 8\mathbf{j})t\ \</math>
		+
		+	0r <math>4\textrm{.}8\mathbf{i}-6\textrm{.}8\mathbf{j}=(4t+0\textrm{.}2\ )\mathbf{i}– (8t+0\textrm{.}3\ )\mathbf{j}\ \</math>

Ian: New page: We have $\mathbf{a}=4\mathbf{i}– 8\mathbf{j},\ \$ $\mathbf{u}=4\mathbf{i}– 8\mathbf{j}\ \$ and $\ \ \mathbf{ r}_{0}=6\mathbf{i}+2\mathbf{j}$ . The ...

Ian — Tue, 13 Apr 2010 16:26:13 GMT

New page: We have <math>\mathbf{a}=4\mathbf{i}– 8\mathbf{j},\ \</math> <math>\mathbf{u}=4\mathbf{i}– 8\mathbf{j}\ \</math> and <math>\ \ \mathbf{ r}_{0}=6\mathbf{i}+2\mathbf{j}</math>. The ...

New page

We have <math>\mathbf{a}=4\mathbf{i}– 8\mathbf{j},\ \</math> <math>\mathbf{u}=4\mathbf{i}– 8\mathbf{j}\ \</math> and <math>\ \ \mathbf{ r}_{0}=6\mathbf{i}+2\mathbf{j}</math>.

The most suitable equation to use is <math>\mathbf{v}=\mathbf{u}+\mathbf{a}t\ \</math>.

Substituting the above values gives a vector eqaution for <math>t</math>.

<math>4\textrm{.}8\mathbf{i}-6\textrm{.}8\mathbf{j}=4\mathbf{i}– 8\mathbf{j}+(4\mathbf{i}– 8\mathbf{j})t\ \</math>

Solution 8.4c - Revision history

Ian at 16:48, 13 April 2010

Ian at 16:38, 13 April 2010

Ian: New page: We have \mathbf{a}=4\mathbf{i}– 8\mathbf{j},\ \ \mathbf{u}=4\mathbf{i}– 8\mathbf{j}\ \ and \ \ \mathbf{ r}_{0}=6\mathbf{i}+2\mathbf{j}. The ...

Ian: New page: We have $\mathbf{a}=4\mathbf{i}– 8\mathbf{j},\ \$ $\mathbf{u}=4\mathbf{i}– 8\mathbf{j}\ \$ and $\ \ \mathbf{ r}_{0}=6\mathbf{i}+2\mathbf{j}$ . The ...