Ian: New page: $t=0\ \$ gives $\mathbf{r}=\left( 2\times 0-16 \right)\mathbf{i}+\left( 4\times 0-12 \right)\mathbf{j}=-16\mathbf{i}-12\mathbf{j}\ \text{m}$ $t=40\ \$ g...

Ian — Sun, 11 Apr 2010 11:25:08 GMT

New page: <math>t=0\ \</math> gives <math>\mathbf{r}=\left( 2\times 0-16 \right)\mathbf{i}+\left( 4\times 0-12 \right)\mathbf{j}=-16\mathbf{i}-12\mathbf{j}\ \text{m}</math> <math>t=40\ \</math> g...

New page

<math>t=0\ \</math> gives

<math>\mathbf{r}=\left( 2\times 0-16 \right)\mathbf{i}+\left( 4\times 0-12 \right)\mathbf{j}=-16\mathbf{i}-12\mathbf{j}\ \text{m}</math>

<math>t=40\ \</math> gives

<math>\mathbf{r}=\left( 2\times 40-16 \right)\mathbf{i}+\left( 4\times 40-12 \right)\mathbf{j}=64\mathbf{i}+144\mathbf{j}\ \text{m}</math>

<math>t=80\ \</math> gives

<math>\mathbf{r}=\left( 2\times 80-16 \right)\mathbf{i}+\left( 4\times 80-12 \right)\mathbf{j}=144\mathbf{i}+308\mathbf{j}\ \text{m}</math>

<math>t=120\ \</math> gives

<math>\mathbf{r}=\left( 2\times 120-16 \right)\mathbf{i}+\left( 4\times 120-12 \right)\mathbf{j}=224\mathbf{i}+468\mathbf{j}\ \text{m}</math>

Solution 7.3a - Revision history

Ian: New page: t=0\ \ gives \mathbf{r}=\left( 2\times 0-16 \right)\mathbf{i}+\left( 4\times 0-12 \right)\mathbf{j}=-16\mathbf{i}-12\mathbf{j}\ \text{m} t=40\ \ g...

Ian: New page: $t=0\ \$ gives $\mathbf{r}=\left( 2\times 0-16 \right)\mathbf{i}+\left( 4\times 0-12 \right)\mathbf{j}=-16\mathbf{i}-12\mathbf{j}\ \text{m}$ $t=40\ \$ g...