Ian: New page: Using ${{v}^{\ 2}}={{u}^{\ 2}}+2as\ \$ gives $\begin{align} & {{24}^{2}}-{{9}^{2}}=2\times a\times 495 \\ & 576-81=990 \times a \\ & a=\frac{495}{990}=0\textrm{.}5\ \tex...$

Ian — Thu, 08 Apr 2010 16:12:30 GMT

New page: Using <math>{{v}^{\ 2}}={{u}^{\ 2}}+2as\ \</math> gives <math>\begin{align} & {{24}^{2}}-{{9}^{2}}=2\times a\times 495 \\ & 576-81=990 \times a \\ & a=\frac{495}{990}=0\textrm{.}5\ \tex...

New page

Using <math>{{v}^{\ 2}}={{u}^{\ 2}}+2as\ \</math> gives

<math>\begin{align}
& {{24}^{2}}-{{9}^{2}}=2\times a\times 495 \\
& 576-81=990 \times a \\
& a=\frac{495}{990}=0\textrm{.}5\ \text{m}{{\text{s}}^{-2}} \\
\end{align}</math>

Solution 6.6a - Revision history

Ian: New page: Using {{v}^{\ 2}}={{u}^{\ 2}}+2as\ \ gives \begin{align} & {{24}^{2}}-{{9}^{2}}=2\times a\times 495 \\ & 576-81=990 \times a \\ & a=\frac{495}{990}=0\textrm{.}5\ \tex...

Ian: New page: Using ${{v}^{\ 2}}={{u}^{\ 2}}+2as\ \$ gives $\begin{align} & {{24}^{2}}-{{9}^{2}}=2\times a\times 495 \\ & 576-81=990 \times a \\ & a=\frac{495}{990}=0\textrm{.}5\ \tex...$