Ian at 15:33, 2 April 2010

Ian — Fri, 02 Apr 2010 15:33:32 GMT

←Older revision		Revision as of 15:33, 2 April 2010
Line 1:		Line 1:
-	Here <math>F\le \mu N</math>	+	Here <math>F\le \mu R</math>

	<math>\mu</math>		<math>\mu</math>

Ian: New page: Here $F\le \mu N$ $\mu$ is the coefficient of friction. $\begin{align} & 67\textrm{.}0<\mu 184 \\ & \\ & \mu >\frac{67\textrm{.}0}{184} \\ & \\ & \mu >0\...$

Ian — Thu, 01 Apr 2010 17:50:19 GMT

New page: Here <math>F\le \mu N</math> <math>\mu</math> is the coefficient of friction. <math>\begin{align} & 67\textrm{.}0<\mu 184 \\ & \\ & \mu >\frac{67\textrm{.}0}{184} \\ & \\ & \mu >0\...

New page

Here <math>F\le \mu N</math>

<math>\mu</math>
is the coefficient of friction.

<math>\begin{align}
& 67\textrm{.}0<\mu 184 \\
& \\
& \mu >\frac{67\textrm{.}0}{184} \\
& \\ & \mu >0\textrm{.}364 \\
\end{align}</math>

Solution 5.1d - Revision history

Ian at 15:33, 2 April 2010

Ian: New page: Here F\le \mu N \mu is the coefficient of friction. \begin{align} & 67\textrm{.}0<\mu 184 \\ & \\ & \mu >\frac{67\textrm{.}0}{184} \\ & \\ & \mu >0\...

Ian: New page: Here $F\le \mu N$ $\mu$ is the coefficient of friction. $\begin{align} & 67\textrm{.}0<\mu 184 \\ & \\ & \mu >\frac{67\textrm{.}0}{184} \\ & \\ & \mu >0\...$