Ian at 15:48, 23 March 2010

Ian — Tue, 23 Mar 2010 15:48:16 GMT

←Older revision		Revision as of 15:48, 23 March 2010
Line 2:		Line 2:
	& \mathbf{F}1=37\textrm{.}6\mathbf{i}+13\textrm{.}7\mathbf{j}\ \text{N}\\		& \mathbf{F}1=37\textrm{.}6\mathbf{i}+13\textrm{.}7\mathbf{j}\ \text{N}\\
	\end{align}</math>		\end{align}</math>
-

	<math>\begin{align}		<math>\begin{align}
	& \mathbf{F}2=43\textrm{.}3\mathbf{i}+25\mathbf{j} \ \text{N}\\		& \mathbf{F}2=43\textrm{.}3\mathbf{i}+25\mathbf{j} \ \text{N}\\
	\end{align}</math>		\end{align}</math>
		+
		+	Resultant force=
		+	<math>F1+F2=\left( 37\textrm{.}6+43\textrm{.}3 \right)\mathbf{i}+\left( 13\textrm{.}7-25 \right)\mathbf{j}=80\textrm{.}9\mathbf{i}-11\textrm{.}3\mathbf{j}\ \text{N}</math>
		+
		+
		+	This vector has magnitude
		+	<math>\sqrt{{{80\textrm{.}9}^{2}}+{{\left( -11\textrm{.}3 \right)}^{2}}} \ \text{=81}\text{.7}\ \text{N}</math>
		+
		+	using
		+
		+	<math>{{F}^{2}}={{H}^{2}}+{{V}^{2}}</math>
		+
		+	where
		+
		+	<math>H=80\textrm{.}9\ \text{N},\ \ V=-11\textrm{.}3\ \text{N}</math>

Ian: New page: $\begin{align} & \mathbf{F}1=37\textrm{.}6\mathbf{i}+13\textrm{.}7\mathbf{j}\ \text{N}\\ \end{align}$ $\begin{align} & \mathbf{F}2=43\textrm{.}3\mathbf{i}+25\mathbf{j} \...$

Ian — Tue, 23 Mar 2010 15:27:02 GMT

New page: <math>\begin{align} & \mathbf{F}1=37\textrm{.}6\mathbf{i}+13\textrm{.}7\mathbf{j}\ \text{N}\\ \end{align}</math> <math>\begin{align} & \mathbf{F}2=43\textrm{.}3\mathbf{i}+25\mathbf{j} \...

New page

<math>\begin{align}
& \mathbf{F}1=37\textrm{.}6\mathbf{i}+13\textrm{.}7\mathbf{j}\ \text{N}\\
\end{align}</math>

<math>\begin{align}
& \mathbf{F}2=43\textrm{.}3\mathbf{i}+25\mathbf{j} \ \text{N}\\
\end{align}</math>

Solution 4.6b - Revision history

Ian at 15:48, 23 March 2010

Ian: New page: \begin{align} & \mathbf{F}1=37\textrm{.}6\mathbf{i}+13\textrm{.}7\mathbf{j}\ \text{N}\\ \end{align} \begin{align} & \mathbf{F}2=43\textrm{.}3\mathbf{i}+25\mathbf{j} \...

Ian: New page: $\begin{align} & \mathbf{F}1=37\textrm{.}6\mathbf{i}+13\textrm{.}7\mathbf{j}\ \text{N}\\ \end{align}$ $\begin{align} & \mathbf{F}2=43\textrm{.}3\mathbf{i}+25\mathbf{j} \...$