Solution 3.9b - Revision history

Ian at 11:30, 27 March 2011

Ian — Sun, 27 Mar 2011 11:30:48 GMT

←Older revision		Revision as of 11:30, 27 March 2011
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-	[[Image:3.9b.gif]]	+	[[Image:3.9bNew.gif]]

	Friction will "try" and prevent motion that is achieve equilibrium.		Friction will "try" and prevent motion that is achieve equilibrium.

Ian at 16:30, 3 February 2011

Ian — Thu, 03 Feb 2011 16:30:44 GMT

←Older revision		Revision as of 16:30, 3 February 2011
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	Also the maximum friction possible is		Also the maximum friction possible is
-	<math>\mu R=0.4\times 1960=784\ \text{N}</math>.	+	<math>\mu R=0\textrm{.}4\times 1960=784\ \text{N}</math>.


	<math>F=760\ \text{N}</math>		<math>F=760\ \text{N}</math>
	falls inside this maximum value and thus is the value of the friction.		falls inside this maximum value and thus is the value of the friction.

Ian: New page: Image:3.9b.gif Friction will "try" and prevent motion that is achieve equilibrium. $\begin{align} & \text{For}\ \text{equilibrium}\ P-F=0 \\ & \text{that}\ \text{is}\ F=760\ \...$

Ian — Fri, 19 Mar 2010 15:57:41 GMT

New page: Image:3.9b.gif Friction will "try" and prevent motion that is achieve equilibrium. <math>\begin{align} & \text{For}\ \text{equilibrium}\ P-F=0 \\ & \text{that}\ \text{is}\ F=760\ \...

New page

[[Image:3.9b.gif]]

Friction will "try" and prevent motion that is achieve equilibrium.

<math>\begin{align}
& \text{For}\ \text{equilibrium}\ P-F=0 \\
& \text{that}\ \text{is}\ F=760\ \text{N} \\
\end{align}</math>

Also the maximum friction possible is
<math>\mu R=0.4\times 1960=784\ \text{N}</math>.

<math>F=760\ \text{N}</math>
falls inside this maximum value and thus is the value of the friction.

Solution 3.9b - Revision history

Ian at 11:30, 27 March 2011

Ian at 16:30, 3 February 2011

Ian: New page: Image:3.9b.gif Friction will "try" and prevent motion that is achieve equilibrium. \begin{align} & \text{For}\ \text{equilibrium}\ P-F=0 \\ & \text{that}\ \text{is}\ F=760\ \...

Ian: New page: Image:3.9b.gif Friction will "try" and prevent motion that is achieve equilibrium. $\begin{align} & \text{For}\ \text{equilibrium}\ P-F=0 \\ & \text{that}\ \text{is}\ F=760\ \...$