Ian at 17:08, 26 March 2011

Ian — Sat, 26 Mar 2011 17:08:04 GMT

←Older revision		Revision as of 17:08, 26 March 2011
Line 4:		Line 4:
	First consider the lower mass.		First consider the lower mass.

-	If <math>T=T1</math> is the tension in the lower string then	+	If <math>T={{T}_{1}}</math> is the tension in the lower string then


Line 11:		Line 11:

	giving		giving
-	<math>T1=68\textrm{.}6\ \text{N}</math>	+	<math>{{T}_{1}}=68\textrm{.}6\ \text{N}</math>


-	If <math>T=T2</math> is the tension in the upper string then the two masses are regarded as one particle with total mass 15 kg.	+	If <math>T={{T}_{2}}</math> is the tension in the upper string then the two masses are regarded as one particle with total mass 15 kg.

	Thus in this case		Thus in this case
Line 23:		Line 23:

	giving		giving
-	<math>T2=147\ \text{N}</math>	+	<math>{{T}_{2}}=147\ \text{N}</math>

Ian: New page: Image:2.1.gif First consider the lower mass. If $T=T1$ is the tension in the lower string then $mg=7\times 9\textrm{.}8=68\textrm{....$

Ian — Wed, 17 Mar 2010 09:59:43 GMT

New page: Image:2.1.gif First consider the lower mass. If <math>T=T1</math> is the tension in the lower string then <math>mg=7\times 9\textrm{.}8=68\textrm{....

New page

[[Image:2.1.gif]]

First consider the lower mass.

If <math>T=T1</math> is the tension in the lower string then

<math>mg=7\times 9\textrm{.}8=68\textrm{.}6\ \text{N}</math>

giving
<math>T1=68\textrm{.}6\ \text{N}</math>

If <math>T=T2</math> is the tension in the upper string then the two masses are regarded as one particle with total mass 15 kg.

Thus in this case

<math>mg=15\times 9\textrm{.}8=147\ \text{N}</math>

giving
<math>T2=147\ \text{N}</math>

Solution 3.3 - Revision history

Ian at 17:08, 26 March 2011

Ian: New page: Image:2.1.gif First consider the lower mass. If T=T1 is the tension in the lower string then mg=7\times 9\textrm{.}8=68\textrm{....

Ian: New page: Image:2.1.gif First consider the lower mass. If $T=T1$ is the tension in the lower string then $mg=7\times 9\textrm{.}8=68\textrm{....$