Ian: New page: Firstly, the angular speed must be converted to standard units. $\omega =400\text{ rpm }=\text{ }\frac{400\times 2\pi }{\text{60}}=\frac{40\pi }{3}\text{ rad}{{\text{s}}^{\text{-1}}}...$

Ian — Tue, 12 Oct 2010 13:03:15 GMT

New page: Firstly, the angular speed must be converted to standard units. <math>\omega =400\text{ rpm }=\text{ }\frac{400\times 2\pi }{\text{60}}=\frac{40\pi }{3}\text{ rad}{{\text{s}}^{\text{-1}}}...

New page

Firstly, the angular speed must be converted to standard units.

<math>\omega =400\text{ rpm }=\text{ }\frac{400\times 2\pi }{\text{60}}=\frac{40\pi }{3}\text{ rad}{{\text{s}}^{\text{-1}}}</math>

<math>\begin{align}
& T=mr{{\omega }^{2}} \\
& =2\times 0\textrm{.}5\times {{\left( \frac{40\pi }{3} \right)}^{2}} \\
& =1755\text{ N}
\end{align}</math>

Solution 20.1 - Revision history

Ian: New page: Firstly, the angular speed must be converted to standard units. \omega =400\text{ rpm }=\text{ }\frac{400\times 2\pi }{\text{60}}=\frac{40\pi }{3}\text{ rad}{{\text{s}}^{\text{-1}}}...

Ian: New page: Firstly, the angular speed must be converted to standard units. $\omega =400\text{ rpm }=\text{ }\frac{400\times 2\pi }{\text{60}}=\frac{40\pi }{3}\text{ rad}{{\text{s}}^{\text{-1}}}...$