Ian: New page: The expression for the velocity $\mathbf{v}$ has been obtained in part b), $\begin{align} & \mathbf{r}=\int{\mathbf{v}}dt \\ & \\ & =\left( \frac{{{t}^{3}}}{2}-8t+{{d}_...$

Ian — Mon, 11 Oct 2010 16:31:29 GMT

New page: The expression for the velocity <math>\mathbf{v}</math> has been obtained in part b), <math>\begin{align} & \mathbf{r}=\int{\mathbf{v}}dt \\ & \\ & =\left( \frac{{{t}^{3}}}{2}-8t+{{d}_...

New page

The expression for the velocity <math>\mathbf{v}</math> has been obtained in part b),

<math>\begin{align}
& \mathbf{r}=\int{\mathbf{v}}dt \\
& \\
& =\left( \frac{{{t}^{3}}}{2}-8t+{{d}_{1}} \right)\mathbf{i}+\left( \frac{3{{t}^{2}}}{4}-\frac{5{{t}^{3}}}{24}+{{d}_{2}} \right)\mathbf{j} \\
& \\
& t=0,\ \mathbf{r}=90\mathbf{i}+20\mathbf{j}\ \Rightarrow \ {{d}_{1}}=90,\ {{d}_{2}}=20 \\
& \\
& \mathbf{r}=\left( \frac{{{t}^{3}}}{2}-8t+90 \right)\mathbf{i}+\left( \frac{3{{t}^{2}}}{4}-\frac{5{{t}^{3}}}{24}+20 \right)\mathbf{j}
\end{align}</math>

Solution 19.7c - Revision history

Ian: New page: The expression for the velocity \mathbf{v} has been obtained in part b), \begin{align} & \mathbf{r}=\int{\mathbf{v}}dt \\ & \\ & =\left( \frac{{{t}^{3}}}{2}-8t+{{d}_...

Ian: New page: The expression for the velocity $\mathbf{v}$ has been obtained in part b), $\begin{align} & \mathbf{r}=\int{\mathbf{v}}dt \\ & \\ & =\left( \frac{{{t}^{3}}}{2}-8t+{{d}_...$