Ian: New page: $\begin{align} & s=\int_{0}^{10}{\left( 3{{t}^{2}}+2t+5 \right)}dt \\ & \\ & =\left[ {{t}^{3}}+{{t}^{2}}+5t \right]_{0}^{10} \\ & \\ & =\left( {{10}^{3}}+{{10}^{2}}+5\times 10 \...$

Ian — Mon, 11 Oct 2010 15:57:04 GMT

New page: <math>\begin{align} & s=\int_{0}^{10}{\left( 3{{t}^{2}}+2t+5 \right)}dt \\ & \\ & =\left[ {{t}^{3}}+{{t}^{2}}+5t \right]_{0}^{10} \\ & \\ & =\left( {{10}^{3}}+{{10}^{2}}+5\times 10 \...

New page

<math>\begin{align}
& s=\int_{0}^{10}{\left( 3{{t}^{2}}+2t+5 \right)}dt \\
& \\
& =\left[ {{t}^{3}}+{{t}^{2}}+5t \right]_{0}^{10} \\
& \\
& =\left( {{10}^{3}}+{{10}^{2}}+5\times 10 \right)-0 \\
& \\
& =1150\text{ m}
\end{align}</math>

Solution 19.6b - Revision history

Ian: New page: \begin{align} & s=\int_{0}^{10}{\left( 3{{t}^{2}}+2t+5 \right)}dt \\ & \\ & =\left[ {{t}^{3}}+{{t}^{2}}+5t \right]_{0}^{10} \\ & \\ & =\left( {{10}^{3}}+{{10}^{2}}+5\times 10 \...

Ian: New page: $\begin{align} & s=\int_{0}^{10}{\left( 3{{t}^{2}}+2t+5 \right)}dt \\ & \\ & =\left[ {{t}^{3}}+{{t}^{2}}+5t \right]_{0}^{10} \\ & \\ & =\left( {{10}^{3}}+{{10}^{2}}+5\times 10 \...$