Ian: New page: As the intercept is 0 and the gradient is $\frac{8000}{20}=400$ , using the equation for a straight line, the force at a time $t$ is given by: $F=400t+0=400t<...$

Ian — Mon, 11 Oct 2010 13:44:28 GMT

New page: As the intercept is 0 and the gradient is <math>\frac{8000}{20}=400</math> , using the equation for a straight line, the force at a time <math>t</math> is given by: <math>F=400t+0=400t<...

New page

As the intercept is 0 and the gradient is
<math>\frac{8000}{20}=400</math>
, using the equation for a straight line, the force at a time
<math>t</math>
is given by:

<math>F=400t+0=400t</math>

As the mass is 1000 kg, using Newtons's second law, the acceleration is given by:

<math>a=\frac{F}{1000}=\frac{400t}{1000}=\frac{2t}{5}</math>

Solution 19.4a - Revision history

Ian: New page: As the intercept is 0 and the gradient is \frac{8000}{20}=400 , using the equation for a straight line, the force at a time t is given by: F=400t+0=400t<...

Ian: New page: As the intercept is 0 and the gradient is $\frac{8000}{20}=400$ , using the equation for a straight line, the force at a time $t$ is given by: $F=400t+0=400t<...$