Ian: New page: $\begin{align} & 3{{t}^{2}}+20t=500 \\ & 3{{t}^{2}}+20t-500=0 \\ & (3t+50)(t-10)=0 \\ & t=-\frac{50}{3}\text{ or }t=10 \\ & \text{It is at a height of 500 m when }t=10 \text { s...$

Ian — Fri, 08 Oct 2010 18:21:31 GMT

New page: <math>\begin{align} & 3{{t}^{2}}+20t=500 \\ & 3{{t}^{2}}+20t-500=0 \\ & (3t+50)(t-10)=0 \\ & t=-\frac{50}{3}\text{ or }t=10 \\ & \text{It is at a height of 500 m when }t=10 \text { s...

New page

<math>\begin{align}
& 3{{t}^{2}}+20t=500 \\
& 3{{t}^{2}}+20t-500=0 \\
& (3t+50)(t-10)=0 \\
& t=-\frac{50}{3}\text{ or }t=10 \\
& \text{It is at a height of 500 m when }t=10 \text { s}, \\
& \text{(the negative solution has no physical meaning). }\\
\end{align}</math>

Solution 18.7a - Revision history

Ian: New page: \begin{align} & 3{{t}^{2}}+20t=500 \\ & 3{{t}^{2}}+20t-500=0 \\ & (3t+50)(t-10)=0 \\ & t=-\frac{50}{3}\text{ or }t=10 \\ & \text{It is at a height of 500 m when }t=10 \text { s...

Ian: New page: $\begin{align} & 3{{t}^{2}}+20t=500 \\ & 3{{t}^{2}}+20t-500=0 \\ & (3t+50)(t-10)=0 \\ & t=-\frac{50}{3}\text{ or }t=10 \\ & \text{It is at a height of 500 m when }t=10 \text { s...$