Ian: New page: As the brick has no speed at the start $\text {KE = KE gained}$ . $\begin{align} & \text {KE gained=PE }\text{ lost }=\text{2}\times \text{9}\text{.8}\times \text{3}\text{...$

Ian — Thu, 30 Sep 2010 09:22:51 GMT

New page: As the brick has no speed at the start <math>\text {KE = KE gained}</math>. <math>\begin{align} & \text {KE gained=PE }\text{ lost }=\text{2}\times \text{9}\text{.8}\times \text{3}\text{...

New page

As the brick has no speed at the start

<math>\text {KE = KE gained}</math>.

<math>\begin{align}
& \text {KE gained=PE }\text{ lost }=\text{2}\times \text{9}\text{.8}\times \text{3}\text{.2}=\text{62}\text{.72 J} \\
& \\
& \frac{\text{1}}{\text{2}}\times 2{{v}^{2}}=62\textrm{.}72 \\
& v=7\textrm{.}92\text{ m}{{\text{s}}^{\text{-1}}}
\end{align}</math>

Solution 17.4a - Revision history

Ian: New page: As the brick has no speed at the start \text {KE = KE gained}. \begin{align} & \text {KE gained=PE }\text{ lost }=\text{2}\times \text{9}\text{.8}\times \text{3}\text{...

Ian: New page: As the brick has no speed at the start $\text {KE = KE gained}$ . $\begin{align} & \text {KE gained=PE }\text{ lost }=\text{2}\times \text{9}\text{.8}\times \text{3}\text{...$