Ian at 18:32, 15 September 2010

Ian — Wed, 15 Sep 2010 18:32:10 GMT

←Older revision		Revision as of 18:32, 15 September 2010
Line 1:		Line 1:
-	<math>I=\text{ }0\textrm{.}\text{64}\ \text{kg}~~\,\text{m}{{\text{s}}^{-1}},~~\quad t=\text{ }0\textrm{.}\text{2}\ \text{s}</math>	+	<math>I=\text{ }0\textrm{.}\text{64} \ \text{Ns}\quad t=\text{ }0\textrm{.}\text{2}\ \text{s}</math>

	<math>\begin{align}		<math>\begin{align}

Ian: New page: $I=\text{ }0\textrm{.}\text{64}\ \text{kg}\,\text{m}{{\text{s}}^{-1}},\quad t=\text{ }0\textrm{.}\text{2}\ \text{s}$ $\begin{align} & \\ & I=Ft \\ & 0\textrm{.}64=F\tim...$

Ian — Wed, 15 Sep 2010 17:19:08 GMT

New page: <math>I=\text{ }0\textrm{.}\text{64}\ \text{kg}\,\text{m}{{\text{s}}^{-1}},\quad t=\text{ }0\textrm{.}\text{2}\ \text{s}</math> <math>\begin{align} & \\ & I=Ft \\ & 0\textrm{.}64=F\tim...

New page

<math>I=\text{ }0\textrm{.}\text{64}\ \text{kg}\,\text{m}{{\text{s}}^{-1}},\quad t=\text{ }0\textrm{.}\text{2}\ \text{s}</math>

<math>\begin{align}
& \\
& I=Ft \\
& 0\textrm{.}64=F\times 0\textrm{.}2 \\
& F=3\textrm{.}2\text{ N}
\end{align}</math>

Solution 15.5b - Revision history

Ian at 18:32, 15 September 2010

Ian: New page: I=\text{ }0\textrm{.}\text{64}\ \text{kg}\,\text{m}{{\text{s}}^{-1}},\quad t=\text{ }0\textrm{.}\text{2}\ \text{s} \begin{align} & \\ & I=Ft \\ & 0\textrm{.}64=F\tim...

Ian: New page: $I=\text{ }0\textrm{.}\text{64}\ \text{kg}\,\text{m}{{\text{s}}^{-1}},\quad t=\text{ }0\textrm{.}\text{2}\ \text{s}$ $\begin{align} & \\ & I=Ft \\ & 0\textrm{.}64=F\tim...$