Ian at 16:27, 27 March 2011

Ian — Sun, 27 Mar 2011 16:27:46 GMT

←Older revision		Revision as of 16:27, 27 March 2011
Line 1:		Line 1:
-	~~First find the impulse (change in momentum).~~	+	4 tonnes = 4000 kg
		+	<math>\ \ cm = 4000</math>
		+	<math>\ \ u = 25</math>
		+	<math>\ \ v = 8</math>

	<math>\begin{align}		<math>\begin{align}
-	& ~~\text{Impulse }~~=mv-mu \\	+	& I=mv-mu \\
-	& ~~1200~~\times 15-~~1200~~\times 20 \\	+	& 4000\times 8-4000\times 25 \\
-	& =-~~6000~~\text{ Ns}	+	& =32000-100000 \\
		+	& =-68000\text{ Ns}
	\end{align}</math>		\end{align}</math>

-		+	Magnitude of the Impulse = 68000 Ns
-	~~Use~~ the ~~formula~~	+
-		+
-	~~<math>\text{~~Impulse }=~~Ft</math>~~	+
-		+
-		+
-		+
-	~~<math>\begin{align}~~	+
-	~~& -6000=F\times 20 \\~~	+
-	~~& F=-300\text{ N} \\~~	+
-	~~\end{align}</math>~~	+

Ian: New page: First find the impulse (change in momentum). $\begin{align} & \text{Impulse }=mv-mu \\ & 1200\times 15-1200\times 20 \\ & =-6000\text{ Ns} \end{align}$ Use the formula ...

Ian — Tue, 14 Sep 2010 17:02:31 GMT

New page: First find the impulse (change in momentum). <math>\begin{align} & \text{Impulse }=mv-mu \\ & 1200\times 15-1200\times 20 \\ & =-6000\text{ Ns} \end{align}</math> Use the formula ...

New page

First find the impulse (change in momentum).

<math>\begin{align}
& \text{Impulse }=mv-mu \\
& 1200\times 15-1200\times 20 \\
& =-6000\text{ Ns}
\end{align}</math>

Use the formula

<math>\text{Impulse }=Ft</math>

<math>\begin{align}
& -6000=F\times 20 \\
& F=-300\text{ N} \\
\end{align}</math>

Solution 15.3 - Revision history

Ian at 16:27, 27 March 2011

Ian: New page: First find the impulse (change in momentum). \begin{align} & \text{Impulse }=mv-mu \\ & 1200\times 15-1200\times 20 \\ & =-6000\text{ Ns} \end{align} Use the formula ...

Ian: New page: First find the impulse (change in momentum). $\begin{align} & \text{Impulse }=mv-mu \\ & 1200\times 15-1200\times 20 \\ & =-6000\text{ Ns} \end{align}$ Use the formula ...