Ian: New page: In this case the reaction at the left hand support will be zero. Taking moments about the right hand support: $\begin{align} & 1\times 18\times 9\textrm{.}8=2\times m\times 9\textrm...$

Ian — Thu, 02 Sep 2010 12:35:13 GMT

New page: In this case the reaction at the left hand support will be zero. Taking moments about the right hand support: <math>\begin{align} & 1\times 18\times 9\textrm{.}8=2\times m\times 9\textrm...

New page

In this case the reaction at the left hand support will be zero. Taking moments about the right hand support:

<math>\begin{align}
& 1\times 18\times 9\textrm{.}8=2\times m\times 9\textrm{.}8 \\
& m=\frac{1\times 18\times 9\textrm{.}8}{2\times 9\textrm{.}8}=9\text{ kg} \\
\end{align}</math>

Solution 14.4b - Revision history

Ian: New page: In this case the reaction at the left hand support will be zero. Taking moments about the right hand support: \begin{align} & 1\times 18\times 9\textrm{.}8=2\times m\times 9\textrm...

Ian: New page: In this case the reaction at the left hand support will be zero. Taking moments about the right hand support: $\begin{align} & 1\times 18\times 9\textrm{.}8=2\times m\times 9\textrm...$