Solution 14.3 - Revision history

Ian at 17:03, 10 March 2011

Ian — Thu, 10 Mar 2011 17:03:17 GMT

←Older revision		Revision as of 17:03, 10 March 2011
Line 30:		Line 30:
	<math>\begin{align}		<math>\begin{align}
	& {{R}_{A}}+114\textrm{.}3=49+196 \\		& {{R}_{A}}+114\textrm{.}3=49+196 \\
-	& {{R}_{A}}=49+196-114\textrm{.}3=130.7\text{ N} \\	+	& {{R}_{A}}=49+196-114\textrm{.}3=130\textrm{.}7\text{ N} \\
	\end{align}</math>		\end{align}</math>

Ian at 14:03, 2 September 2010

Ian — Thu, 02 Sep 2010 14:03:40 GMT

←Older revision		Revision as of 14:03, 2 September 2010
Line 3:		Line 3:


-	[[Image:14.3.gif]]	+	[[Image:14.3a.gif]]

Ian: New page: The diagram shows the forces acting. Image:14.3.gif Taking moments about the left hand support: $\begin{align} & {{R}_{B}}\times 3=49\times 1+196\times 1\textrm{.}5 \\ & ...$

Ian — Thu, 02 Sep 2010 12:21:25 GMT

New page: The diagram shows the forces acting. Image:14.3.gif Taking moments about the left hand support: <math>\begin{align} & {{R}_{B}}\times 3=49\times 1+196\times 1\textrm{.}5 \\ & ...

New page

The diagram shows the forces acting.

[[Image:14.3.gif]]

Taking moments about the left hand support:

<math>\begin{align}
& {{R}_{B}}\times 3=49\times 1+196\times 1\textrm{.}5 \\
& {{R}_{B}}=\frac{49\times 1+196\times 1\textrm{.}5}{3}=114\textrm{.}3\text{ N} \\
\end{align}</math>

Taking moments about the right hand support:

<math>\begin{align}
& {{R}_{A}}\times 3=49\times 2+196\times 1\textrm{.}5 \\
& {{R}_{B}}=\frac{49\times 2+196\times 1\textrm{.}5}{3}=130\textrm{.}7\text{ N} \\
\end{align}</math>

Or:

<math>\begin{align}
& {{R}_{A}}+114\textrm{.}3=49+196 \\
& {{R}_{A}}=49+196-114\textrm{.}3=130.7\text{ N} \\
\end{align}</math>

Solution 14.3 - Revision history

Ian at 17:03, 10 March 2011

Ian at 14:03, 2 September 2010

Ian: New page: The diagram shows the forces acting. Image:14.3.gif Taking moments about the left hand support: \begin{align} & {{R}_{B}}\times 3=49\times 1+196\times 1\textrm{.}5 \\ & ...

Ian: New page: The diagram shows the forces acting. Image:14.3.gif Taking moments about the left hand support: $\begin{align} & {{R}_{B}}\times 3=49\times 1+196\times 1\textrm{.}5 \\ & ...$