Ian: New page: In this case ${{R}_{B}}=0$ . Taking moments about A: $\begin{align} & 0\textrm{.}5\times 20\times 9\textrm{.}8=1\times m\times 9\textrm{.}8 \\ & m=\frac{0\textrm{.}5\ti...$

Ian — Wed, 01 Sep 2010 18:29:32 GMT

New page: In this case <math>{{R}_{B}}=0</math>. Taking moments about A: <math>\begin{align} & 0\textrm{.}5\times 20\times 9\textrm{.}8=1\times m\times 9\textrm{.}8 \\ & m=\frac{0\textrm{.}5\ti...

New page

In this case
<math>{{R}_{B}}=0</math>. Taking moments about A:

<math>\begin{align}
& 0\textrm{.}5\times 20\times 9\textrm{.}8=1\times m\times 9\textrm{.}8 \\
& m=\frac{0\textrm{.}5\times 20\times 9\textrm{.}8}{1\times 9\textrm{.}8}=10\text{ kg} \\
\end{align}</math>

Solution 14.1b - Revision history

Ian: New page: In this case {{R}_{B}}=0. Taking moments about A: \begin{align} & 0\textrm{.}5\times 20\times 9\textrm{.}8=1\times m\times 9\textrm{.}8 \\ & m=\frac{0\textrm{.}5\ti...

Ian: New page: In this case ${{R}_{B}}=0$ . Taking moments about A: $\begin{align} & 0\textrm{.}5\times 20\times 9\textrm{.}8=1\times m\times 9\textrm{.}8 \\ & m=\frac{0\textrm{.}5\ti...$