17. Exercises - Revision history

Ian at 13:27, 27 April 2011

Ian — Wed, 27 Apr 2011 13:27:39 GMT

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	{{Not selected tab\|[[17. Conservation of energy\|Theory]]}}		{{Not selected tab\|[[17. Conservation of energy\|Theory]]}}
	{{Selected tab\|[[17. Exercises\|Exercises]]}}		{{Selected tab\|[[17. Exercises\|Exercises]]}}
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Ian — Sun, 27 Mar 2011 16:49:15 GMT

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	<div class="ovning">		<div class="ovning">

-	A child of mass 40 kg, slides ~~rom~~ rest down a water slide. The difference in height between the start and end of the water slide is 12 m.	+	A child of mass 40 kg, slides from rest down a water slide. The difference in height between the start and end of the water slide is 12 m.

	a) Assume that there is no resistance to the motion on the slide and calculate the speed of the child at the bottom of the slide.		a) Assume that there is no resistance to the motion on the slide and calculate the speed of the child at the bottom of the slide.

Ian — Sun, 27 Mar 2011 16:48:16 GMT

←Older revision		Revision as of 16:48, 27 March 2011
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	<div class="ovning">		<div class="ovning">

-	A child of mass 40 kg, slides down a water slide. The difference in height between the start and end of the water slide is 12 m.	+	A child of mass 40 kg, slides rom rest down a water slide. The difference in height between the start and end of the water slide is 12 m.

	a) Assume that there is no resistance to the motion on the slide and calculate the speed of the child at the bottom of the slide.		a) Assume that there is no resistance to the motion on the slide and calculate the speed of the child at the bottom of the slide.

Ian — Mon, 04 Oct 2010 12:00:58 GMT

←Older revision		Revision as of 12:00, 4 October 2010
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-	</div>{{#NAVCONTENT:Answer a\|Answer 17.7a\|Answer b\|Answer 17.7b\|Solution a\|Solution 17.7a\|Solution b\|Solution 17.7b}}	+	</div>{{#NAVCONTENT:Answer a\|Answer 17.9a\|Answer b\|Answer 17.9b\|Solution a\|Solution 17.9a\|Solution b\|Solution 17.9b}}

Ian — Mon, 04 Oct 2010 11:56:23 GMT

←Older revision		Revision as of 11:56, 4 October 2010
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-	</div>{{#NAVCONTENT:Answer a\|Answer 17.7a\|Answer b\|Answer 17.8b\|Solution a\|Solution 17.8a}}	+	</div>{{#NAVCONTENT:Answer a\|Answer 17.8a\|Answer b\|Answer 17.8b\|Solution a\|Solution 17.8a}}

Ian — Sat, 02 Oct 2010 12:21:09 GMT

←Older revision		Revision as of 12:21, 2 October 2010
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	[[Image:E17.6.GIF]]		[[Image:E17.6.GIF]]

-	a) Calculate the initial ~~kinetic~~ energy of the particle.	+	a) Calculate the initial potential energy of the particle.

	b) Find the speed of the particle when the string is vertical.		b) Find the speed of the particle when the string is vertical.

Ian — Mon, 16 Nov 2009 13:26:06 GMT

Ian — Mon, 16 Nov 2009 13:24:48 GMT

←Older revision		Revision as of 13:24, 16 November 2009
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	b) Find maximum angle between the string and the vertical.		b) Find maximum angle between the string and the vertical.
		+
		+
		+	</div>{{#NAVCONTENT:Answer a\|Answer 17.7a\|Answer b\|Answer 17.7b\|Solution a\|Solution 17.7a\|Solution b\|Solution 17.7b}}
		+
		+
		+
		+	===Exercise 17.8===
		+	<div class="ovning">
		+
		+	A ball football is kicked so that it leaves the ground travelling at 18 <math>\text{m}{{\text{s}}^{-1}}</math>. As it moves its speed drops to a minimum of 12 <math>\text{m}{{\text{s}}^{-1}}</math>.
		+
		+	a) Find the maximum height of the ball.
		+
		+	b) Explain why you did not need to know the mass of the ball.
		+
		+
		+
		+	</div>{{#NAVCONTENT:Answer a\|Answer 17.7a\|Answer b\|Answer 17.8b\|Solution a\|Solution 17.8a}}
		+
		+
		+	===Exercise 17.7===
		+	<div class="ovning">
		+
		+	A child of mass 40 kg, slides down a water slide. The difference in height between the start and end of the water slide is 12 m.
		+
		+	a) Assume that there is no resistance to the motion on the slide and calculate the speed of the child at the bottom of the slide.
		+
		+	b) If the speed of the child at the bottom of the slide is 8 <math>\text{m}{{\text{s}}^{-1}}</math>, calculate how much energy has been lost as the child moved down the slide.


	</div>{{#NAVCONTENT:Answer a\|Answer 17.7a\|Answer b\|Answer 17.7b\|Solution a\|Solution 17.7a\|Solution b\|Solution 17.7b}}		</div>{{#NAVCONTENT:Answer a\|Answer 17.7a\|Answer b\|Answer 17.7b\|Solution a\|Solution 17.7a\|Solution b\|Solution 17.7b}}

Ian — Mon, 16 Nov 2009 13:03:21 GMT

←Older revision		Revision as of 13:03, 16 November 2009
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	</div>{{#NAVCONTENT:Answer a\|Answer 17.6a\|Answer b\|Answer 17.6b\|Answer c\|Answer 17.6c\|Solution a\|Solution 17.6a\|Solution b\|Solution 17.6b\|Solution c\|Solution 17.6c}}		</div>{{#NAVCONTENT:Answer a\|Answer 17.6a\|Answer b\|Answer 17.6b\|Answer c\|Answer 17.6c\|Solution a\|Solution 17.6a\|Solution b\|Solution 17.6b\|Solution c\|Solution 17.6c}}
		+
		+
		+
		+	===Exercise 17.7===
		+	<div class="ovning">
		+
		+	A simple pendulum consists of a particle of mass 0.05 kg and a light string of length 0.8 m. When the string is vertical, the particle is moving at a speed of 1.2 <math>\text{m}{{\text{s}}^{-1}}</math>.
		+
		+	a) Calculate the initial kinetic energy of the particle.
		+
		+	b) Find maximum angle between the string and the vertical.
		+
		+
		+	</div>{{#NAVCONTENT:Answer a\|Answer 17.7a\|Answer b\|Answer 17.7b\|Solution a\|Solution 17.7a\|Solution b\|Solution 17.7b}}

Ian — Sun, 15 Nov 2009 18:02:53 GMT

←Older revision		Revision as of 18:02, 15 November 2009
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	</div>{{#NAVCONTENT:Answer a\|Answer 17.5a\|Answer b\|Answer 17.5b\|Answer c\|Answer 17.5c\|Solution a\|Solution 17.5a\|Solution b\|Solution 17.5b\|Solution c\|Solution 17.5c}}		</div>{{#NAVCONTENT:Answer a\|Answer 17.5a\|Answer b\|Answer 17.5b\|Answer c\|Answer 17.5c\|Solution a\|Solution 17.5a\|Solution b\|Solution 17.5b\|Solution c\|Solution 17.5c}}
		+
		+
		+
		+	===Exercise 17.6===
		+	<div class="ovning">
		+
		+	A particle of mass 5 kg is attached to the end of a rope of length 8 metres. The other end of the rope is fixed. The particle is released from rest with the rope at an angle of 30<math>{}^\circ </math> to the vertical as shown in the diagram.
		+
		+	[[Image:E17.6.GIF]]
		+
		+	a) Calculate the initial kinetic energy of the particle.
		+
		+	b) Find the speed of the particle when the string is vertical.
		+
		+	c) As the particle swings it looses some energy due to air resistance. Because of this the string makes an angle of 28<math>{}^\circ </math> with the vertical when the string is on the opposite side to the starting position. Calculate how much energy was lost during the first swing.
		+
		+
		+
		+	</div>{{#NAVCONTENT:Answer a\|Answer 17.6a\|Answer b\|Answer 17.6b\|Answer c\|Answer 17.6c\|Solution a\|Solution 17.6a\|Solution b\|Solution 17.6b\|Solution c\|Solution 17.6c}}

←Older revision		Revision as of 13:27, 27 April 2011
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	{{Not selected tab\|[[17. Conservation of energy\|Theory]]}}		{{Not selected tab\|[[17. Conservation of energy\|Theory]]}}
	{{Selected tab\|[[17. Exercises\|Exercises]]}}		{{Selected tab\|[[17. Exercises\|Exercises]]}}
		+	{{Not selected tab\|[[17. Video\|Video]]}}
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