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Solution 8.4b - Revision history
2026-05-28T06:08:24Z
Revision history for this page on the wiki
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http://wiki.sommarmatte.se/wikis/2009/bridgecoursemechanics/index.php?title=Solution_8.4b&diff=1051&oldid=prev
Ian at 14:18, 14 April 2010
2010-04-14T14:18:24Z
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<td colspan='2' style="background-color: white; color:black;">←Older revision</td>
<td colspan='2' style="background-color: white; color:black;">Revision as of 14:18, 14 April 2010</td>
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<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>Using <math>\mathbf{r}=\mathbf{u}t+\frac{1}{2}\mathbf{a}{{t}^{\ 2}}+{{\mathbf{r}}_{0}}</math> at <math>\ \ t=10</math> gives </div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>Using <math>\mathbf{r}=\mathbf{u}t+\frac{1}{2}\mathbf{a}{{t}^{\ 2}}+{{\mathbf{r}}_{0}}</math> at <math>\ \ t=10</math> gives </div></td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"></td></tr>
<tr><td class='diff-marker'>-</td><td style="background: #ffa; color:black; font-size: smaller;"><div><del style="color: red; font-weight: bold; text-decoration: none;">Using </del><math>\mathbf{r}=(4\mathbf{i}– 8\mathbf{j}) \times 10+\frac{1}{2}(0\textrm{.}2\mathbf{i}+0\textrm{.}3\mathbf{j}) \times {{10}^{\ 2}}+6\mathbf{i}+2\mathbf{j}</math></div></td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div><math>\mathbf{r}=(4\mathbf{i}– 8\mathbf{j}) \times 10+\frac{1}{2}(0\textrm{.}2\mathbf{i}+0\textrm{.}3\mathbf{j}) \times {{10}^{\ 2}}+6\mathbf{i}+2\mathbf{j}</math></div></td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"></td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><math>\mathbf{r}=56\mathbf{i}– 63\mathbf{j}\ \ \text{m}{{\text{s}}^{-1}}</math></div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><math>\mathbf{r}=56\mathbf{i}– 63\mathbf{j}\ \ \text{m}{{\text{s}}^{-1}}</math></div></td></tr>
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Ian
http://wiki.sommarmatte.se/wikis/2009/bridgecoursemechanics/index.php?title=Solution_8.4b&diff=1041&oldid=prev
Ian: New page: Here we have <math>\mathbf{a}=0\textrm{.}2\mathbf{i}+0\textrm{.}3\mathbf{j},\ \</math> <math>\mathbf{u}=4\mathbf{i}– 8\mathbf{j}\ \</math> and <math>\ \ \mathbf{ r}_{0}=6\mathbf{i}...
2010-04-13T16:19:33Z
<p>New page: Here we have <math>\mathbf{a}=0\textrm{.}2\mathbf{i}+0\textrm{.}3\mathbf{j},\ \</math> <math>\mathbf{u}=4\mathbf{i}– 8\mathbf{j}\ \</math> and <math>\ \ \mathbf{ r}_{0}=6\mathbf{i}...</p>
<p><b>New page</b></p><div>Here we have <math>\mathbf{a}=0\textrm{.}2\mathbf{i}+0\textrm{.}3\mathbf{j},\ \</math> <br />
<math>\mathbf{u}=4\mathbf{i}– 8\mathbf{j}\ \</math> and <br />
<math>\ \ \mathbf{ r}_{0}=6\mathbf{i}+2\mathbf{j}</math>.<br />
<br />
Using <math>\mathbf{r}=\mathbf{u}t+\frac{1}{2}\mathbf{a}{{t}^{\ 2}}+{{\mathbf{r}}_{0}}</math> at <math>\ \ t=10</math> gives <br />
<br />
Using <math>\mathbf{r}=(4\mathbf{i}– 8\mathbf{j}) \times 10+\frac{1}{2}(0\textrm{.}2\mathbf{i}+0\textrm{.}3\mathbf{j}) \times {{10}^{\ 2}}+6\mathbf{i}+2\mathbf{j}</math><br />
<br />
<math>\mathbf{r}=56\mathbf{i}– 63\mathbf{j}\ \ \text{m}{{\text{s}}^{-1}}</math></div>
Ian