Solution 8.1b - Revision history

Ian at 15:28, 13 April 2010

2010-04-13T15:28:28Z

←Older revision		Revision as of 15:28, 13 April 2010
Line 8:		Line 8:
	Substituting these into the equation		Substituting these into the equation
	<math>\mathbf{r}=\mathbf{u}t+\frac{1}{2}\mathbf{a}{{t}^{\ 2}}+{{\mathbf{r}}_{0}}</math>		<math>\mathbf{r}=\mathbf{u}t+\frac{1}{2}\mathbf{a}{{t}^{\ 2}}+{{\mathbf{r}}_{0}}</math>
-	gives the position vector of the ~~particle~~ at time <math>t=10 \text{ s }</math> as:	+	gives the position vector of the jet-ski at time <math>t=10 \text{ s }</math> as:

	<math>\begin{align}		<math>\begin{align}

Ian at 15:26, 13 April 2010

2010-04-13T15:26:21Z

←Older revision		Revision as of 15:26, 13 April 2010
Line 8:		Line 8:
	Substituting these into the equation		Substituting these into the equation
	<math>\mathbf{r}=\mathbf{u}t+\frac{1}{2}\mathbf{a}{{t}^{\ 2}}+{{\mathbf{r}}_{0}}</math>		<math>\mathbf{r}=\mathbf{u}t+\frac{1}{2}\mathbf{a}{{t}^{\ 2}}+{{\mathbf{r}}_{0}}</math>
-	gives the position vector of the ~~ball~~ at time <math>t=10 \text{ s }</math> as:	+	gives the position vector of the particle at time <math>t=10 \text{ s }</math> as:

	<math>\begin{align}		<math>\begin{align}

Ian at 14:50, 13 April 2010

2010-04-13T14:50:20Z

←Older revision		Revision as of 14:50, 13 April 2010
Line 7:		Line 7:

	Substituting these into the equation		Substituting these into the equation
-	<math>\mathbf{r}=\mathbf{u}t+\frac{1}{2}\mathbf{a}{{t}^{\ 2}}+~~400~~\mathbf{i}~~+350\mathbf~~{j}</math>	+	<math>\mathbf{r}=\mathbf{u}t+\frac{1}{2}\mathbf{a}{{t}^{\ 2}}+{{\mathbf{r}}_{0}}</math>
	gives the position vector of the ball at time <math>t=10 \text{ s }</math> as:		gives the position vector of the ball at time <math>t=10 \text{ s }</math> as:

Ian: New page: In this case we have $\mathbf{u}=4\mathbf{i}$ , $\mathbf{a}=0\textrm{.}9\mathbf{i}+0\textrm{.}7\mathbf{j}$ and ${{\mathbf{r}}_{0}}=400\mathbf{i}+350\mathbf{j}...$

2010-04-12T17:24:00Z

New page: In this case we have <math>\mathbf{u}=4\mathbf{i}</math> , <math>\mathbf{a}=0\textrm{.}9\mathbf{i}+0\textrm{.}7\mathbf{j}</math> and <math>{{\mathbf{r}}_{0}}=400\mathbf{i}+350\mathbf{j}...

New page

In this case we have
<math>\mathbf{u}=4\mathbf{i}</math>
,
<math>\mathbf{a}=0\textrm{.}9\mathbf{i}+0\textrm{.}7\mathbf{j}</math>
and
<math>{{\mathbf{r}}_{0}}=400\mathbf{i}+350\mathbf{j}</math>.

Substituting these into the equation
<math>\mathbf{r}=\mathbf{u}t+\frac{1}{2}\mathbf{a}{{t}^{\ 2}}+400\mathbf{i}+350\mathbf{j}</math>
gives the position vector of the ball at time <math>t=10 \text{ s }</math> as:

<math>\begin{align}
& \mathbf{r}=(4\mathbf{i})\times 10+\frac{1}{2}(0\textrm{.}9\mathbf{i}+0\textrm{.}7\mathbf{j})\times {{10}^{\ 2}}+400\mathbf{i}+350\mathbf{j} \\
& =40\mathbf{i}+45\mathbf{i}+35\mathbf{j}+400\mathbf{i}+350\mathbf{j} \\ \\
& =485\mathbf{i}+385\mathbf{j} \ \text{m}
\end{align}</math>

Solution 8.1b - Revision history

Ian at 15:28, 13 April 2010

Ian at 15:26, 13 April 2010

Ian at 14:50, 13 April 2010

Ian: New page: In this case we have \mathbf{u}=4\mathbf{i} , \mathbf{a}=0\textrm{.}9\mathbf{i}+0\textrm{.}7\mathbf{j} and {{\mathbf{r}}_{0}}=400\mathbf{i}+350\mathbf{j}...

Ian: New page: In this case we have $\mathbf{u}=4\mathbf{i}$ , $\mathbf{a}=0\textrm{.}9\mathbf{i}+0\textrm{.}7\mathbf{j}$ and ${{\mathbf{r}}_{0}}=400\mathbf{i}+350\mathbf{j}...$