Ian: New page: The area under the velocity-time graph gives the distance travelled. This area can be calculated by breaking up the area into three parts, two triangles and a rectangle This method gives...

2010-04-07T09:21:32Z

New page: The area under the velocity-time graph gives the distance travelled. This area can be calculated by breaking up the area into three parts, two triangles and a rectangle This method gives...

New page

The area under the velocity-time graph gives the distance travelled.

This area can be calculated by breaking up the area into three parts, two triangles and a rectangle

This method gives (we ignore units in the calculation)

<math>\frac{1}{2}\left( 3\times 2 \right)+\left( \left[ 7-3 \right]\times 2 \right)+\frac{1}{2}\left( \left[ 9-7 \right]\times 2 \right)=13\text{ m}</math>

Solution 6.3a - Revision history

Ian: New page: The area under the velocity-time graph gives the distance travelled. This area can be calculated by breaking up the area into three parts, two triangles and a rectangle This method gives...