Ian: New page: Image:5.5.gif The horisontal component $H$ of the 5000 N force is $H=5000\cos {{25}^{\circ }}=4531\ \text{N}$ The maximum friction is $\mu R=0.3\times...$

2010-04-04T16:47:52Z

New page: Image:5.5.gif The horisontal component <math>H</math> of the 5000 N force is <math>H=5000\cos {{25}^{\circ }}=4531\ \text{N}</math> The maximum friction is <math>\mu R=0.3\times...

New page

[[Image:5.5.gif]]

The horisontal component
<math>H</math>
of the 5000 N force is

<math>H=5000\cos {{25}^{\circ }}=4531\ \text{N}</math>

The maximum friction is
<math>\mu R=0.3\times 2787=836\ \text{N}</math>

This is less then
<math>H</math>. Thus the maximum friction
<math>836\ \text{N}</math>
will come into play.

Solution 5.5c - Revision history

Ian: New page: Image:5.5.gif The horisontal component H of the 5000 N force is H=5000\cos {{25}^{\circ }}=4531\ \text{N} The maximum friction is \mu R=0.3\times...

Ian: New page: Image:5.5.gif The horisontal component $H$ of the 5000 N force is $H=5000\cos {{25}^{\circ }}=4531\ \text{N}$ The maximum friction is $\mu R=0.3\times...$