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Solution 5.2a - Revision history
2026-05-28T08:46:06Z
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http://wiki.sommarmatte.se/wikis/2009/bridgecoursemechanics/index.php?title=Solution_5.2a&diff=951&oldid=prev
Ian at 16:01, 2 April 2010
2010-04-02T16:01:00Z
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<td colspan='2' style="background-color: white; color:black;">Revision as of 16:01, 2 April 2010</td>
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<tr><td class='diff-marker'>-</td><td style="background: #ffa; color:black; font-size: smaller;"><div>Resolving vertically</div></td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div>Resolving vertically <ins style="color: red; font-weight: bold; text-decoration: none;">upwards</ins></div></td></tr>
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Ian
http://wiki.sommarmatte.se/wikis/2009/bridgecoursemechanics/index.php?title=Solution_5.2a&diff=949&oldid=prev
Ian: New page: Resolving vertically <math>\begin{align} & {{T}_{1}}\cos {{50}^{\circ }}-mg=0 \\ & \\ & {{T}_{1}}=\frac{mg}{\cos {{50}^{\circ }}}=\frac{490}{0\textrm{.}643}=762\ \text{N} \\ \end{ali...
2010-04-02T15:54:59Z
<p>New page: Resolving vertically <math>\begin{align} & {{T}_{1}}\cos {{50}^{\circ }}-mg=0 \\ & \\ & {{T}_{1}}=\frac{mg}{\cos {{50}^{\circ }}}=\frac{490}{0\textrm{.}643}=762\ \text{N} \\ \end{ali...</p>
<p><b>New page</b></p><div>Resolving vertically<br />
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<math>\begin{align}<br />
& {{T}_{1}}\cos {{50}^{\circ }}-mg=0 \\ <br />
& \\ <br />
& {{T}_{1}}=\frac{mg}{\cos {{50}^{\circ }}}=\frac{490}{0\textrm{.}643}=762\ \text{N} \\ <br />
\end{align}</math></div>
Ian