Ian: New page: The forces on the particle are in equilibrium as the particle is at rest. The sum of the forces up the plane (resolving up the plane) $\begin{align} & F-mg\sin {{20}^{\circ }}=0 \\...$

2010-04-01T17:39:03Z

New page: The forces on the particle are in equilibrium as the particle is at rest. The sum of the forces up the plane (resolving up the plane) <math>\begin{align} & F-mg\sin {{20}^{\circ }}=0 \\...

New page

The forces on the particle are in equilibrium as the particle is at rest.

The sum of the forces up the plane (resolving up the plane)

<math>\begin{align}
& F-mg\sin {{20}^{\circ }}=0 \\
& \\
& F=mg\sin {{20}^{\circ }}=20\times 9\textrm{.}8\times 0\textrm{.}342=67\textrm{.}0\ \text{N} \\
\end{align}</math>

Solution 5.1c - Revision history

Ian: New page: The forces on the particle are in equilibrium as the particle is at rest. The sum of the forces up the plane (resolving up the plane) \begin{align} & F-mg\sin {{20}^{\circ }}=0 \\...

Ian: New page: The forces on the particle are in equilibrium as the particle is at rest. The sum of the forces up the plane (resolving up the plane) $\begin{align} & F-mg\sin {{20}^{\circ }}=0 \\...$