http://wiki.sommarmatte.se/wikis/2009/bridgecoursemechanics/index.php?action=history&feed=atom&title=Solution_4.6c
Solution 4.6c - Revision history
2026-04-08T05:16:27Z
Revision history for this page on the wiki
MediaWiki 1.11.1
http://wiki.sommarmatte.se/wikis/2009/bridgecoursemechanics/index.php?title=Solution_4.6c&diff=1579&oldid=prev
Ian at 16:13, 4 February 2011
2011-02-04T16:13:54Z
<p></p>
<table style="background-color: white; color:black;">
<col class='diff-marker' />
<col class='diff-content' />
<col class='diff-marker' />
<col class='diff-content' />
<tr>
<td colspan='2' style="background-color: white; color:black;">←Older revision</td>
<td colspan='2' style="background-color: white; color:black;">Revision as of 16:13, 4 February 2011</td>
</tr>
<tr><td colspan="2" class="diff-lineno">Line 4:</td>
<td colspan="2" class="diff-lineno">Line 4:</td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>Thus</div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>Thus</div></td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"></td></tr>
<tr><td class='diff-marker'>-</td><td style="background: #ffa; color:black; font-size: smaller;"><div><math>\tan \alpha =\frac{-11\textrm{.}3}{80.9}=-0\textrm{.}14</math></div></td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div><math>\tan \alpha =\frac{-11\textrm{.}3}{80<ins style="color: red; font-weight: bold; text-decoration: none;">\textrm{</ins>.<ins style="color: red; font-weight: bold; text-decoration: none;">}</ins>9}=-0\textrm{.}14</math></div></td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"></td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>giving</div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>giving</div></td></tr>
</table>
Ian
http://wiki.sommarmatte.se/wikis/2009/bridgecoursemechanics/index.php?title=Solution_4.6c&diff=907&oldid=prev
Ian at 16:02, 23 March 2010
2010-03-23T16:02:29Z
<p></p>
<table style="background-color: white; color:black;">
<col class='diff-marker' />
<col class='diff-content' />
<col class='diff-marker' />
<col class='diff-content' />
<tr>
<td colspan='2' style="background-color: white; color:black;">←Older revision</td>
<td colspan='2' style="background-color: white; color:black;">Revision as of 16:02, 23 March 2010</td>
</tr>
<tr><td colspan="2" class="diff-lineno">Line 11:</td>
<td colspan="2" class="diff-lineno">Line 11:</td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"></td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>As the vector is in the fourth quadrant</div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>As the vector is in the fourth quadrant</div></td></tr>
<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"></td></tr>
<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div>[[Image:4.6c.gif]]</div></td></tr>
</table>
Ian
http://wiki.sommarmatte.se/wikis/2009/bridgecoursemechanics/index.php?title=Solution_4.6c&diff=905&oldid=prev
Ian: New page: Resultant force <math>=80\textrm{.}9\mathbf{i}-11\textrm{.}3\mathbf{j}\ \text{N}</math> Thus <math>\tan \alpha =\frac{-11\textrm{.}3}{80.9}=-0\textrm{.}14</math> giving <math>\alpha =-...
2010-03-23T15:58:20Z
<p>New page: Resultant force <math>=80\textrm{.}9\mathbf{i}-11\textrm{.}3\mathbf{j}\ \text{N}</math> Thus <math>\tan \alpha =\frac{-11\textrm{.}3}{80.9}=-0\textrm{.}14</math> giving <math>\alpha =-...</p>
<p><b>New page</b></p><div>Resultant force<br />
<math>=80\textrm{.}9\mathbf{i}-11\textrm{.}3\mathbf{j}\ \text{N}</math><br />
<br />
Thus<br />
<br />
<math>\tan \alpha =\frac{-11\textrm{.}3}{80.9}=-0\textrm{.}14</math><br />
<br />
giving<br />
<br />
<math>\alpha =-8\textrm{.}0{}^\circ</math><br />
<br />
As the vector is in the fourth quadrant</div>
Ian