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		<title>Solution 3.8 - Revision history</title>
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		<updated>2026-05-28T13:01:18Z</updated>
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		<id>http://wiki.sommarmatte.se/wikis/2009/bridgecoursemechanics/index.php?title=Solution_3.8&amp;diff=844&amp;oldid=prev</id>
		<title>Ian: New page: See diagram.   &lt;math&gt;R1&lt;/math&gt; is the reaction force holding up the combined weights of the two lighter boxes. Equilibrium of the two boxes gives  &lt;math&gt;\begin{align} &amp; \uparrow \ R1-(5+10...</title>
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				<updated>2010-03-19T13:26:21Z</updated>
		
		<summary type="html">&lt;p&gt;New page: See diagram.   &amp;lt;math&amp;gt;R1&amp;lt;/math&amp;gt; is the reaction force holding up the combined weights of the two lighter boxes. Equilibrium of the two boxes gives  &amp;lt;math&amp;gt;\begin{align} &amp;amp; \uparrow \ R1-(5+10...&lt;/p&gt;
&lt;p&gt;&lt;b&gt;New page&lt;/b&gt;&lt;/p&gt;&lt;div&gt;See diagram.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;R1&amp;lt;/math&amp;gt;&lt;br /&gt;
is the reaction force holding up the combined weights of the two lighter boxes.&lt;br /&gt;
Equilibrium of the two boxes gives&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;\begin{align}&lt;br /&gt;
&amp;amp; \uparrow \ R1-(5+10)g=0 \\ &lt;br /&gt;
&amp;amp; \text{giving}\ R1=15\times 9\textrm{.}8=147\ \text{N} \\ &lt;br /&gt;
\end{align}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
The weight is &lt;br /&gt;
&amp;lt;math&amp;gt;mg=12\times 9\textrm{.}8=117\textrm{.}6\ \text{N}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
Finally the box is in equilibrium &lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;\begin{align}&lt;br /&gt;
&amp;amp; \uparrow \ R2-R1-mg=0 \\ &lt;br /&gt;
&amp;amp; \text{giving}\ R2=147+117\textrm{.}6=264\textrm{.}6\ \text{N} \\ &lt;br /&gt;
\end{align}&amp;lt;/math&amp;gt;&lt;/div&gt;</summary>
		<author><name>Ian</name></author>	</entry>

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