Ian: New page: Vertically the forces on the tank are in equilibrium $\begin{align} & \uparrow \ R-mg=0 \\ & R=800\times 9\textrm{.}8=7840\ \text{N} \\ \end{align}$ The maximum friction is ...

2010-03-22T10:33:33Z

New page: Vertically the forces on the tank are in equilibrium <math>\begin{align} & \uparrow \ R-mg=0 \\ & R=800\times 9\textrm{.}8=7840\ \text{N} \\ \end{align}</math> The maximum friction is ...

New page

Vertically the forces on the tank are in equilibrium

<math>\begin{align}
& \uparrow \ R-mg=0 \\
& R=800\times 9\textrm{.}8=7840\ \text{N} \\
\end{align}</math>

The maximum friction is thus,

<math>F=\mu R=0\textrm{.}6\times 7840=4704\ \text{N}</math>

This is less than the force exerted by the rope. Thus resultant horisontal force is

<math>\leftarrow \ 5000-4704=296\ \text{N}</math>

Solution 3.13bc - Revision history

Ian: New page: Vertically the forces on the tank are in equilibrium \begin{align} & \uparrow \ R-mg=0 \\ & R=800\times 9\textrm{.}8=7840\ \text{N} \\ \end{align} The maximum friction is ...

Ian: New page: Vertically the forces on the tank are in equilibrium $\begin{align} & \uparrow \ R-mg=0 \\ & R=800\times 9\textrm{.}8=7840\ \text{N} \\ \end{align}$ The maximum friction is ...