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		<title>Solution 20.6a - Revision history</title>
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		<updated>2026-04-08T06:55:59Z</updated>
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	<entry>
		<id>http://wiki.sommarmatte.se/wikis/2009/bridgecoursemechanics/index.php?title=Solution_20.6a&amp;diff=1512&amp;oldid=prev</id>
		<title>Ian: New page: The maximum value for the  speed &lt;math&gt;v&lt;/math&gt; is determined by the maximum value which the frictional force &lt;math&gt;F&lt;/math&gt;can assume which is:  &lt;math&gt;F=\mu R&lt;/math&gt; gives  &lt;math&gt;\begin{a...</title>
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				<updated>2010-10-12T14:59:54Z</updated>
		
		<summary type="html">&lt;p&gt;New page: The maximum value for the  speed &amp;lt;math&amp;gt;v&amp;lt;/math&amp;gt; is determined by the maximum value which the frictional force &amp;lt;math&amp;gt;F&amp;lt;/math&amp;gt;can assume which is:  &amp;lt;math&amp;gt;F=\mu R&amp;lt;/math&amp;gt; gives  &amp;lt;math&amp;gt;\begin{a...&lt;/p&gt;
&lt;p&gt;&lt;b&gt;New page&lt;/b&gt;&lt;/p&gt;&lt;div&gt;The maximum value for the  speed &amp;lt;math&amp;gt;v&amp;lt;/math&amp;gt; is determined by the maximum value which the frictional force &amp;lt;math&amp;gt;F&amp;lt;/math&amp;gt;can assume which is:&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;F=\mu R&amp;lt;/math&amp;gt; gives&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;\begin{align}&lt;br /&gt;
&amp;amp; m\frac{{{v}^{2}}}{r}=\mu mg \\ &lt;br /&gt;
&amp;amp; v=\sqrt{\mu rg}=\sqrt{0\textrm{.}8\times 140\times 9\textrm{.}8}=33\textrm{.}1\text{ m}{{\text{s}}^{\text{-1}}} \\ &lt;br /&gt;
\end{align}&amp;lt;/math&amp;gt;&lt;/div&gt;</summary>
		<author><name>Ian</name></author>	</entry>

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