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Solution 19.8a - Revision history
2026-05-27T18:58:16Z
Revision history for this page on the wiki
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http://wiki.sommarmatte.se/wikis/2009/bridgecoursemechanics/index.php?title=Solution_19.8a&diff=1486&oldid=prev
Ian: New page: <math>\begin{align} & \mathbf{v}=\int{\mathbf{a}dt} \\ & \\ & =\left( {{c}_{1}} \right)\mathbf{i}+\left( -2t+{{c}_{2}} \right)\mathbf{j} \\ & \\ & t=0,\ \mathbf{v}=40\mathbf{i}\ \Rig...
2010-10-11T16:50:10Z
<p>New page: <math>\begin{align} & \mathbf{v}=\int{\mathbf{a}dt} \\ & \\ & =\left( {{c}_{1}} \right)\mathbf{i}+\left( -2t+{{c}_{2}} \right)\mathbf{j} \\ & \\ & t=0,\ \mathbf{v}=40\mathbf{i}\ \Rig...</p>
<p><b>New page</b></p><div><math>\begin{align}<br />
& \mathbf{v}=\int{\mathbf{a}dt} \\ <br />
& \\ <br />
& =\left( {{c}_{1}} \right)\mathbf{i}+\left( -2t+{{c}_{2}} \right)\mathbf{j} \\ <br />
& \\ <br />
& t=0,\ \mathbf{v}=40\mathbf{i}\ \Rightarrow \ {{c}_{1}}=40,\ {{c}_{2}}=0 \\ <br />
& \\ <br />
& \mathbf{v}=\left( 40 \right)\mathbf{i}+\left( -2t \right)\mathbf{j} <br />
\end{align}</math></div>
Ian