http://wiki.sommarmatte.se/wikis/2009/bridgecoursemechanics/index.php?action=history&feed=atom&title=Solution_19.7cSolution 19.7c - Revision history2026-05-27T19:00:08ZRevision history for this page on the wikiMediaWiki 1.11.1http://wiki.sommarmatte.se/wikis/2009/bridgecoursemechanics/index.php?title=Solution_19.7c&diff=1480&oldid=prevIan: New page: The expression for the velocity <math>\mathbf{v}</math> has been obtained in part b), <math>\begin{align} & \mathbf{r}=\int{\mathbf{v}}dt \\ & \\ & =\left( \frac{{{t}^{3}}}{2}-8t+{{d}_...2010-10-11T16:31:29Z<p>New page: The expression for the velocity <math>\mathbf{v}</math> has been obtained in part b), <math>\begin{align} & \mathbf{r}=\int{\mathbf{v}}dt \\ & \\ & =\left( \frac{{{t}^{3}}}{2}-8t+{{d}_...</p>
<p><b>New page</b></p><div>The expression for the velocity <math>\mathbf{v}</math> has been obtained in part b),<br />
<br />
<math>\begin{align}<br />
& \mathbf{r}=\int{\mathbf{v}}dt \\ <br />
& \\ <br />
& =\left( \frac{{{t}^{3}}}{2}-8t+{{d}_{1}} \right)\mathbf{i}+\left( \frac{3{{t}^{2}}}{4}-\frac{5{{t}^{3}}}{24}+{{d}_{2}} \right)\mathbf{j} \\ <br />
& \\ <br />
& t=0,\ \mathbf{r}=90\mathbf{i}+20\mathbf{j}\ \Rightarrow \ {{d}_{1}}=90,\ {{d}_{2}}=20 \\ <br />
& \\ <br />
& \mathbf{r}=\left( \frac{{{t}^{3}}}{2}-8t+90 \right)\mathbf{i}+\left( \frac{3{{t}^{2}}}{4}-\frac{5{{t}^{3}}}{24}+20 \right)\mathbf{j} <br />
\end{align}</math></div>Ian