<?xml version="1.0" encoding="utf-8"?>
<?xml-stylesheet type="text/css" href="http://wiki.sommarmatte.se/wikis/2009/bridgecoursemechanics/skins/common/feed.css?97"?>
<feed xmlns="http://www.w3.org/2005/Atom" xml:lang="en">
		<id>http://wiki.sommarmatte.se/wikis/2009/bridgecoursemechanics/index.php?action=history&amp;feed=atom&amp;title=Solution_19.4a</id>
		<title>Solution 19.4a - Revision history</title>
		<link rel="self" type="application/atom+xml" href="http://wiki.sommarmatte.se/wikis/2009/bridgecoursemechanics/index.php?action=history&amp;feed=atom&amp;title=Solution_19.4a"/>
		<link rel="alternate" type="text/html" href="http://wiki.sommarmatte.se/wikis/2009/bridgecoursemechanics/index.php?title=Solution_19.4a&amp;action=history"/>
		<updated>2026-05-27T19:00:07Z</updated>
		<subtitle>Revision history for this page on the wiki</subtitle>
		<generator>MediaWiki 1.11.1</generator>

	<entry>
		<id>http://wiki.sommarmatte.se/wikis/2009/bridgecoursemechanics/index.php?title=Solution_19.4a&amp;diff=1460&amp;oldid=prev</id>
		<title>Ian: New page: As the intercept is 0 and the gradient is  &lt;math&gt;\frac{8000}{20}=400&lt;/math&gt; , using the equation for a straight line, the force at a time  &lt;math&gt;t&lt;/math&gt; is given by:  &lt;math&gt;F=400t+0=400t&lt;...</title>
		<link rel="alternate" type="text/html" href="http://wiki.sommarmatte.se/wikis/2009/bridgecoursemechanics/index.php?title=Solution_19.4a&amp;diff=1460&amp;oldid=prev"/>
				<updated>2010-10-11T13:44:28Z</updated>
		
		<summary type="html">&lt;p&gt;New page: As the intercept is 0 and the gradient is  &amp;lt;math&amp;gt;\frac{8000}{20}=400&amp;lt;/math&amp;gt; , using the equation for a straight line, the force at a time  &amp;lt;math&amp;gt;t&amp;lt;/math&amp;gt; is given by:  &amp;lt;math&amp;gt;F=400t+0=400t&amp;lt;...&lt;/p&gt;
&lt;p&gt;&lt;b&gt;New page&lt;/b&gt;&lt;/p&gt;&lt;div&gt;As the intercept is 0 and the gradient is &lt;br /&gt;
&amp;lt;math&amp;gt;\frac{8000}{20}=400&amp;lt;/math&amp;gt;&lt;br /&gt;
, using the equation for a straight line, the force at a time &lt;br /&gt;
&amp;lt;math&amp;gt;t&amp;lt;/math&amp;gt;&lt;br /&gt;
is given by:&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;F=400t+0=400t&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
As the mass is 1000 kg, using Newtons's second law, the acceleration is given by:&lt;br /&gt;
&lt;br /&gt;
&amp;lt;math&amp;gt;a=\frac{F}{1000}=\frac{400t}{1000}=\frac{2t}{5}&amp;lt;/math&amp;gt;&lt;/div&gt;</summary>
		<author><name>Ian</name></author>	</entry>

	</feed>