http://wiki.sommarmatte.se/wikis/2009/bridgecoursemechanics/index.php?action=history&feed=atom&title=Solution_18.4cSolution 18.4c - Revision history2026-04-08T01:37:32ZRevision history for this page on the wikiMediaWiki 1.11.1http://wiki.sommarmatte.se/wikis/2009/bridgecoursemechanics/index.php?title=Solution_18.4c&diff=1660&oldid=prevIan at 17:12, 27 March 20112011-03-27T17:12:08Z<p></p>
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<td colspan='2' style="background-color: white; color:black;">←Older revision</td>
<td colspan='2' style="background-color: white; color:black;">Revision as of 17:12, 27 March 2011</td>
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<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><math>a=\frac{dv}{dt}=36-6t</math></div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><math>a=\frac{dv}{dt}=36-6t</math></div></td></tr>
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<tr><td class='diff-marker'>-</td><td style="background: #ffa; color:black; font-size: smaller;"><div>We see <math>a</math> decreases as the time <math>t</math> increases. Thus the maximum <del style="color: red; font-weight: bold; text-decoration: none;">acxceleration </del>is at <math>t=0</math> giving </div></td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div>We see <math>a</math> decreases as the time <math>t</math> increases. Thus the maximum <ins style="color: red; font-weight: bold; text-decoration: none;">acceleration </ins>is at <math>t=0</math> giving </div></td></tr>
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<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><math>\text{a}\ \text{=}\ \text{36 m}{{\text{s}}^{-\text{2}}}</math></div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><math>\text{a}\ \text{=}\ \text{36 m}{{\text{s}}^{-\text{2}}}</math></div></td></tr>
</table>Ianhttp://wiki.sommarmatte.se/wikis/2009/bridgecoursemechanics/index.php?title=Solution_18.4c&diff=1397&oldid=prevIan: New page: From part a) <math>a=\frac{dv}{dt}=36-6t</math> We see <math>a</math> decreases as the time <math>t</math> increases. Thus the maximum acxceleration is at <math>t=0</math> giving <math...2010-10-06T17:52:03Z<p>New page: From part a) <math>a=\frac{dv}{dt}=36-6t</math> We see <math>a</math> decreases as the time <math>t</math> increases. Thus the maximum acxceleration is at <math>t=0</math> giving <math...</p>
<p><b>New page</b></p><div>From part a)<br />
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<math>a=\frac{dv}{dt}=36-6t</math><br />
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We see <math>a</math> decreases as the time <math>t</math> increases. Thus the maximum acxceleration is at <math>t=0</math> giving <br />
<br />
<math>\text{a}\ \text{=}\ \text{36 m}{{\text{s}}^{-\text{2}}}</math></div>Ian