http://wiki.sommarmatte.se/wikis/2009/bridgecoursemechanics/index.php?action=history&feed=atom&title=Solution_18.1c
Solution 18.1c - Revision history
2026-04-08T01:38:27Z
Revision history for this page on the wiki
MediaWiki 1.11.1
http://wiki.sommarmatte.se/wikis/2009/bridgecoursemechanics/index.php?title=Solution_18.1c&diff=1652&oldid=prev
Ian at 16:57, 27 March 2011
2011-03-27T16:57:49Z
<p></p>
<table style="background-color: white; color:black;">
<col class='diff-marker' />
<col class='diff-content' />
<col class='diff-marker' />
<col class='diff-content' />
<tr>
<td colspan='2' style="background-color: white; color:black;">←Older revision</td>
<td colspan='2' style="background-color: white; color:black;">Revision as of 16:57, 27 March 2011</td>
</tr>
<tr><td colspan="2" class="diff-lineno">Line 2:</td>
<td colspan="2" class="diff-lineno">Line 2:</td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"></td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><math>\begin{align}</div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><math>\begin{align}</div></td></tr>
<tr><td class='diff-marker'>-</td><td style="background: #ffa; color:black; font-size: smaller;"><div>& 2t-\frac{<del style="color: red; font-weight: bold; text-decoration: none;">3</del>{{t}^{2}}}{<del style="color: red; font-weight: bold; text-decoration: none;">20</del>}=0 \\ </div></td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div>& 2t-\frac{{{t}^{2}}}{<ins style="color: red; font-weight: bold; text-decoration: none;">5</ins>}=0 \\ </div></td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>& \text{which gives } \\ </div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>& \text{which gives } \\ </div></td></tr>
<tr><td class='diff-marker'>-</td><td style="background: #ffa; color:black; font-size: smaller;"><div>& t=0\ \text{s }\ \text{or }\ t=<del style="color: red; font-weight: bold; text-decoration: none;">\frac{40}{3}=13\textrm{.}3</del>\ \text{s} \\ </div></td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div>& t=0\ \text{s }\ \text{or }\ t=<ins style="color: red; font-weight: bold; text-decoration: none;">10</ins>\ \text{s} \\ </div></td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>\end{align}</math></div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>\end{align}</math></div></td></tr>
</table>
Ian
http://wiki.sommarmatte.se/wikis/2009/bridgecoursemechanics/index.php?title=Solution_18.1c&diff=1374&oldid=prev
Ian at 15:30, 4 October 2010
2010-10-04T15:30:40Z
<p></p>
<table style="background-color: white; color:black;">
<col class='diff-marker' />
<col class='diff-content' />
<col class='diff-marker' />
<col class='diff-content' />
<tr>
<td colspan='2' style="background-color: white; color:black;">←Older revision</td>
<td colspan='2' style="background-color: white; color:black;">Revision as of 15:30, 4 October 2010</td>
</tr>
<tr><td colspan="2" class="diff-lineno">Line 3:</td>
<td colspan="2" class="diff-lineno">Line 3:</td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><math>\begin{align}</div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div><math>\begin{align}</div></td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>& 2t-\frac{3{{t}^{2}}}{20}=0 \\ </div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>& 2t-\frac{3{{t}^{2}}}{20}=0 \\ </div></td></tr>
<tr><td class='diff-marker'>-</td><td style="background: #ffa; color:black; font-size: smaller;"><div>& t=0\ \text{s }\ \text{or }\ t=\frac{40}{3}=13.3\ \text{s} \\ </div></td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div><ins style="color: red; font-weight: bold; text-decoration: none;">& \text{which gives } \\ </ins></div></td></tr>
<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="background: #cfc; color:black; font-size: smaller;"><div>& t=0\ \text{s }\ \text{or }\ t=\frac{40}{3}=13<ins style="color: red; font-weight: bold; text-decoration: none;">\textrm{</ins>.<ins style="color: red; font-weight: bold; text-decoration: none;">}</ins>3\ \text{s} \\ </div></td></tr>
<tr><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>\end{align}</math></div></td><td class='diff-marker'> </td><td style="background: #eee; color:black; font-size: smaller;"><div>\end{align}</math></div></td></tr>
</table>
Ian
http://wiki.sommarmatte.se/wikis/2009/bridgecoursemechanics/index.php?title=Solution_18.1c&diff=1373&oldid=prev
Ian: New page: Using the result of part b) with <math>a=0</math> gives <math>\begin{align} & 2t-\frac{3{{t}^{2}}}{20}=0 \\ & t=0\ \text{s }\ \text{or }\ t=\frac{40}{3}=13.3\ \text{s} \\ \end{align}<...
2010-10-04T15:29:18Z
<p>New page: Using the result of part b) with <math>a=0</math> gives <math>\begin{align} & 2t-\frac{3{{t}^{2}}}{20}=0 \\ & t=0\ \text{s }\ \text{or }\ t=\frac{40}{3}=13.3\ \text{s} \\ \end{align}<...</p>
<p><b>New page</b></p><div>Using the result of part b) with <math>a=0</math> gives<br />
<br />
<math>\begin{align}<br />
& 2t-\frac{3{{t}^{2}}}{20}=0 \\ <br />
& t=0\ \text{s }\ \text{or }\ t=\frac{40}{3}=13.3\ \text{s} \\ <br />
\end{align}</math></div>
Ian