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Solution 16.8 - Revision history
2026-05-27T23:01:35Z
Revision history for this page on the wiki
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Ian: New page: <math>\begin{align} & {{\mathbf{u}}_{W}}=\mathbf{i},\ {{\mathbf{v}}_{W}}=0\textrm{.}8\cos 60{}^\circ \mathbf{i}+0.\textrm{.}8\sin 60{}^\circ \mathbf{j} \\ & m(\mathbf{i})=m(0\textrm{.}8\c...
2010-09-29T17:13:06Z
<p>New page: <math>\begin{align} & {{\mathbf{u}}_{W}}=\mathbf{i},\ {{\mathbf{v}}_{W}}=0\textrm{.}8\cos 60{}^\circ \mathbf{i}+0.\textrm{.}8\sin 60{}^\circ \mathbf{j} \\ & m(\mathbf{i})=m(0\textrm{.}8\c...</p>
<p><b>New page</b></p><div><math>\begin{align}<br />
& {{\mathbf{u}}_{W}}=\mathbf{i},\ {{\mathbf{v}}_{W}}=0\textrm{.}8\cos 60{}^\circ \mathbf{i}+0.\textrm{.}8\sin 60{}^\circ \mathbf{j} \\ <br />
& m(\mathbf{i})=m(0\textrm{.}8\cos 60{}^\circ \mathbf{i}+0\textrm{.}8\sin 60{}^\circ \mathbf{j})+m{{\mathbf{v}}_{R}} \\ <br />
& {{\mathbf{v}}_{R}}=(1-0\textrm{.}8\cos 60{}^\circ )\mathbf{i}-0\textrm{.}8\sin 60{}^\circ \mathbf{j} \\ <br />
& =0\textrm{.}6\mathbf{i}-0\textrm{.}6928\mathbf{j} \\ <br />
& {{v}_{R}}=\sqrt{{{0\textrm{.}6}^{2}}+{{0\textrm{.}6928}^{2}}}=0\textrm{.}916\text{ m}{{\text{s}}^{\text{-1}}} <br />
\end{align}</math></div>
Ian