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Solution 15.7a - Revision history
2026-05-28T00:15:06Z
Revision history for this page on the wiki
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Ian: New page: <math>m=\text{ 2}\text{ kg}</math>, <math>\quad \mathbf{u}=12\mathbf{i}\ \text{ m}{{\text{s}}^{-1}}</math>, <math>\quad \mathbf{v}=6\mathbf{j}\ \text{ m}{{\text{s}}^{-1}}</math> <math>\...
2010-09-17T10:33:24Z
<p>New page: <math>m=\text{ 2}\text{ kg}</math>, <math>\quad \mathbf{u}=12\mathbf{i}\ \text{ m}{{\text{s}}^{-1}}</math>, <math>\quad \mathbf{v}=6\mathbf{j}\ \text{ m}{{\text{s}}^{-1}}</math> <math>\...</p>
<p><b>New page</b></p><div><math>m=\text{ 2}\text{ kg}</math>, <br />
<math>\quad \mathbf{u}=12\mathbf{i}\ \text{ m}{{\text{s}}^{-1}}</math>,<br />
<math>\quad \mathbf{v}=6\mathbf{j}\ \text{ m}{{\text{s}}^{-1}}</math><br />
<br />
<br />
<math>\begin{align}<br />
& \mathbf{I}=m\mathbf{v}-m\mathbf{u} \\ <br />
& =2(6\mathbf{j})-2\left( 12\mathbf{i} \right) \\ <br />
& =-24\mathbf{i}+12\mathbf{j} \\ <br />
& I=\sqrt{{{(-24)}^{2}}+{{12}^{2}}} \\ <br />
& =26\textrm{.}8\text{ Ns} <br />
\end{align}</math></div>
Ian