Ian: New page: Image:14.7.gif Using part a, we see from the figure that $F=S=\frac{98}{\tan \theta }$ and $R=196$ $\begin{align} & F\le \mu R \\ & \frac{98}{\tan \the...$

2010-09-14T15:46:10Z

New page: Image:14.7.gif Using part a, we see from the figure that <math>F=S=\frac{98}{\tan \theta }</math> and <math>R=196</math> <math>\begin{align} & F\le \mu R \\ & \frac{98}{\tan \the...

New page

[[Image:14.7.gif]]

Using part a, we see from the figure that

<math>F=S=\frac{98}{\tan \theta }</math>
and
<math>R=196</math>

<math>\begin{align}
& F\le \mu R \\
& \frac{98}{\tan \theta }\le 0\textrm{.}6\times 196 \\
& \tan \theta \ge \frac{98}{0\textrm{.}6\times 196} \\
& \theta \ge 39\textrm{.}8{}^\circ \\
\end{align}</math>

Solution 14.7b - Revision history

Ian: New page: Image:14.7.gif Using part a, we see from the figure that F=S=\frac{98}{\tan \theta } and R=196 \begin{align} & F\le \mu R \\ & \frac{98}{\tan \the...

Ian: New page: Image:14.7.gif Using part a, we see from the figure that $F=S=\frac{98}{\tan \theta }$ and $R=196$ $\begin{align} & F\le \mu R \\ & \frac{98}{\tan \the...$