Solution 13.2 - Revision history

Ian at 10:42, 2 August 2010

2010-08-02T10:42:36Z

←Older revision		Revision as of 10:42, 2 August 2010
Line 1:		Line 1:
	{\| width="100%" cellspacing="10px" align="center"		{\| width="100%" cellspacing="10px" align="center"
	\|align="left"\| Force		\|align="left"\| Force
-	\| valign="top"\|~~Perp. distance(m)~~	+	\| valign="top"\|Perpendicular
	\| valign="top"\|Moment (Nm)		\| valign="top"\|Moment (Nm)
		+	\|-
		+	\|
		+	\| valign="top"\| distance (m)
		+	\| valign="top"\|
	\|-		\|-
	\|8 N at <math>D</math>		\|8 N at <math>D</math>

Ian at 10:39, 2 August 2010

2010-08-02T10:39:29Z

←Older revision		Revision as of 10:39, 2 August 2010
Line 1:		Line 1:
	{\| width="100%" cellspacing="10px" align="center"		{\| width="100%" cellspacing="10px" align="center"
	\|align="left"\| Force		\|align="left"\| Force
		+	\| valign="top"\|Perp. distance(m)
	\| valign="top"\|Moment (Nm)		\| valign="top"\|Moment (Nm)
	\|-		\|-
	\|8 N at <math>D</math>		\|8 N at <math>D</math>
		+	\| valign="top"\|2
	\| valign="top"\| <math>-8\times 2=-16</math>		\| valign="top"\| <math>-8\times 2=-16</math>
	\|-		\|-
	\|20 N at <math>D</math>		\|20 N at <math>D</math>
		+	\| valign="top"\|0
	\|valign="top"\| <math>20\times 0=0</math>		\|valign="top"\| <math>20\times 0=0</math>
	\|-		\|-
	\|18 N at <math>C</math>		\|18 N at <math>C</math>
		+	\| valign="top"\|5
	\| valign="top"\| <math>-18\times 5=-90</math>		\| valign="top"\| <math>-18\times 5=-90</math>
	\|-		\|-
	\|16 N at <math>C</math>		\|16 N at <math>C</math>
		+	\| valign="top"\|2
	\| valign="top"\| <math>16\times 2=32</math>		\| valign="top"\| <math>16\times 2=32</math>
	\|-		\|-
-	\|24 N at <math>B</math>	+	\|24 N at <math>B</math>
		+	\| valign="top"\|0
	\| valign="top"\| <math>24\times 0=0</math>		\| valign="top"\| <math>24\times 0=0</math>
	\|-		\|-

Ian at 11:09, 26 June 2010

2010-06-26T11:09:02Z

←Older revision		Revision as of 11:09, 26 June 2010
Line 17:		Line 17:
	\|24 N at <math>B</math>		\|24 N at <math>B</math>
	\| valign="top"\| <math>24\times 0=0</math>		\| valign="top"\| <math>24\times 0=0</math>
-	\|-
-	\|4 N
-	\| valign="top"\| <math>4\times 0\textrm{.}5=2</math>
	\|-		\|-
	\|Total Moment		\|Total Moment
-	\| valign="top"\| <math>0-~~9\textrm{.}6~~+0-3+6+2=-~~4\textrm{.}6~~\text{ Nm}</math>	+	\| valign="top"\| <math>-16+0-90+32+0=-74\text{ Nm}</math>

	\|}		\|}

Ian at 11:06, 26 June 2010

2010-06-26T11:06:19Z

←Older revision		Revision as of 11:06, 26 June 2010
Line 4:		Line 4:
	\|-		\|-
	\|8 N at <math>D</math>		\|8 N at <math>D</math>
-	\| valign="top"\| <math>-8\times 2=16</math>	+	\| valign="top"\| <math>-8\times 2=-16</math>
	\|-		\|-
	\|20 N at <math>D</math>		\|20 N at <math>D</math>
Line 12:		Line 12:
	\| valign="top"\| <math>-18\times 5=-90</math>		\| valign="top"\| <math>-18\times 5=-90</math>
	\|-		\|-
-	\|6 N	+	\|16 N at <math>C</math>
-	\| valign="top"\| <math>-6\times ~~0\textrm{.}5~~=-3</math>	+	\| valign="top"\| <math>16\times 2=32</math>
	\|-		\|-
-	\|5 N	+	\|24 N at <math>B</math>
-	\| valign="top"\| <math>5\times ~~1\textrm{.}2~~=6</math>	+	\| valign="top"\| <math>24\times 0=0</math>
	\|-		\|-
	\|4 N		\|4 N

Ian: New page: {| width="100%" cellspacing="10px" align="center" |align="left"| Force | valign="top"|Moment (Nm) |- |8 N at $D$ | valign="top"| $-8\times 2=16$ |- |20 N at $...$

2010-06-26T11:03:16Z

New page: {| width="100%" cellspacing="10px" align="center" |align="left"| Force | valign="top"|Moment (Nm) |- |8 N at <math>D</math> | valign="top"| <math>-8\times 2=16</math> |- |20 N at <math>...

New page

{| width="100%" cellspacing="10px" align="center"
|align="left"| Force
| valign="top"|Moment (Nm)
|-
|8 N at <math>D</math>
| valign="top"| <math>-8\times 2=16</math>
|-
|20 N at <math>D</math>
|valign="top"| <math>20\times 0=0</math>
|-
|18 N at <math>C</math>
| valign="top"| <math>-18\times 5=-90</math>
|-
|6 N
| valign="top"| <math>-6\times 0\textrm{.}5=-3</math>
|-
|5 N
| valign="top"| <math>5\times 1\textrm{.}2=6</math>
|-
|4 N
| valign="top"| <math>4\times 0\textrm{.}5=2</math>
|-
|Total Moment
| valign="top"| <math>0-9\textrm{.}6+0-3+6+2=-4\textrm{.}6\text{ Nm}</math>

|}

Solution 13.2 - Revision history

Ian at 10:42, 2 August 2010

Ian at 10:39, 2 August 2010

Ian at 11:09, 26 June 2010

Ian at 11:06, 26 June 2010

Ian: New page: {| width="100%" cellspacing="10px" align="center" |align="left"| Force | valign="top"|Moment (Nm) |- |8 N at D | valign="top"| -8\times 2=16 |- |20 N at ...

Ian: New page: {| width="100%" cellspacing="10px" align="center" |align="left"| Force | valign="top"|Moment (Nm) |- |8 N at $D$ | valign="top"| $-8\times 2=16$ |- |20 N at $...$