http://wiki.sommarmatte.se/wikis/2009/bridgecoursemechanics/index.php?action=history&feed=atom&title=SolutionSolution - Revision history2026-05-28T11:21:19ZRevision history for this page on the wikiMediaWiki 1.11.1http://wiki.sommarmatte.se/wikis/2009/bridgecoursemechanics/index.php?title=Solution&diff=874&oldid=prevIan: New page: The normal force <math>R</math> is equal to the weight <math>mg</math> of the sledge. Thus <math>R=mg=117 \textrm{.}6\ \text{N}</math>. The maximum frictional force is <math>F=\mu R</ma...2010-03-21T16:23:36Z<p>New page: The normal force <math>R</math> is equal to the weight <math>mg</math> of the sledge. Thus <math>R=mg=117 \textrm{.}6\ \text{N}</math>. The maximum frictional force is <math>F=\mu R</ma...</p>
<p><b>New page</b></p><div>The normal force <math>R</math> is equal to the weight <math>mg</math> of the sledge. <br />
<br />
Thus <math>R=mg=117 \textrm{.}6\ \text{N}</math>.<br />
<br />
The maximum frictional force is <math>F=\mu R</math> where the coefficient of friction <math>\mu = 0 \textrm{.}3</math>.<br />
<br />
Thus the maximum frictional force is <math>F=35 \textrm{.}28\text{ N}</math>.<br />
<br />
If <math>P</math> is greater than <math>35 \textrm{.}28\text{ N}</math> then the sledge will accelerate.</div>Ian