Lösung 3.2:6d - Versionsgeschichte

Martin um 13:10, 13. Mai 2009

Martin — Wed, 13 May 2009 13:10:51 GMT

← Nächstältere Version		Version vom 13:10, 13. Mai 2009
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-	~~We can determine the number's magnitude directly using the distance formula~~,	+	Wir berechnen zuerst den Betrag der komplexen Zahl,

	{{Abgesetzte Formel\|\|<math>\begin{align}		{{Abgesetzte Formel\|\|<math>\begin{align}
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	\end{align}</math>}}		\end{align}</math>}}

-	~~In addition~~, ~~the number lies in the first quadrant and we can therefore determine the argument using simple trigonometry~~.	+	Nachdem die Zahl im ersten Quadrant liegt, erhalten wir das Argument durch einfache Trigonometrie.

	[[Image:3_2_6_d_bild.gif]] [[Image:3_2_6_d_bildtext.gif]]		[[Image:3_2_6_d_bild.gif]] [[Image:3_2_6_d_bildtext.gif]]

-	~~The polar form is~~	+	Die Polarform ist also

	{{Abgesetzte Formel\|\|<math>2\sqrt{10}\Bigl( \cos\frac{\pi}{3} + i\sin\frac{\pi}{3} \Bigr)\,\textrm{.}</math>}}		{{Abgesetzte Formel\|\|<math>2\sqrt{10}\Bigl( \cos\frac{\pi}{3} + i\sin\frac{\pi}{3} \Bigr)\,\textrm{.}</math>}}

Tekbot — Wed, 11 Mar 2009 10:41:35 GMT

← Nächstältere Version

Version vom 10:41, 11. Mär. 2009

Tekbot — Tue, 10 Mar 2009 13:10:14 GMT

Robot: Automated text replacement (-{{Displayed math +{{Abgesetzte Formel)

← Nächstältere Version		Version vom 13:10, 10. Mär. 2009
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	We can determine the number's magnitude directly using the distance formula,		We can determine the number's magnitude directly using the distance formula,

-	{{~~Displayed math~~\|\|<math>\begin{align}	+	{{Abgesetzte Formel\|\|<math>\begin{align}
	\bigl\|\sqrt{10}+\sqrt{30}i\bigr\|		\bigl\|\sqrt{10}+\sqrt{30}i\bigr\|
	&= \sqrt{\bigl(\sqrt{10}\,\bigr)^2+\bigl(\sqrt{30}\,\bigr)^2}\\[5pt]		&= \sqrt{\bigl(\sqrt{10}\,\bigr)^2+\bigl(\sqrt{30}\,\bigr)^2}\\[5pt]
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	The polar form is		The polar form is

-	{{~~Displayed math~~\|\|<math>2\sqrt{10}\Bigl( \cos\frac{\pi}{3} + i\sin\frac{\pi}{3} \Bigr)\,\textrm{.}</math>}}	+	{{Abgesetzte Formel\|\|<math>2\sqrt{10}\Bigl( \cos\frac{\pi}{3} + i\sin\frac{\pi}{3} \Bigr)\,\textrm{.}</math>}}

Tek — Wed, 29 Oct 2008 13:56:07 GMT

← Nächstältere Version		Version vom 13:56, 29. Okt. 2008
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-	We can determine the number's magnitude directly using the distance formula	+	We can determine the number's magnitude directly using the distance formula,
-		+
-		+
-	~~<math>\begin{align}~~	+
-	~~& \left\| \sqrt{10}+\sqrt{30}i \right\|=\sqrt{\left( \sqrt{10} \right)^{2}+\left( \sqrt{30} \right)^{2}}=\sqrt{10+30} \\~~	+
-	~~& =\sqrt{40}=\sqrt{4\centerdot 10}=2\sqrt{10} \\~~	+
-	~~\end{align}</math>~~	+

		+	{{Displayed math\|\|<math>\begin{align}
		+	\bigl\|\sqrt{10}+\sqrt{30}i\bigr\|
		+	&= \sqrt{\bigl(\sqrt{10}\,\bigr)^2+\bigl(\sqrt{30}\,\bigr)^2}\\[5pt]
		+	&= \sqrt{10+30}\\[5pt]
		+	&= \sqrt{40}\\[5pt]
		+	&= \sqrt{4\cdot 10}\\[5pt]
		+	&= 2\sqrt{10}\,\textrm{.}
		+	\end{align}</math>}}

	In addition, the number lies in the first quadrant and we can therefore determine the argument using simple trigonometry.		In addition, the number lies in the first quadrant and we can therefore determine the argument using simple trigonometry.
-

	[[Image:3_2_6_d_bild.gif]] [[Image:3_2_6_d_bildtext.gif]]		[[Image:3_2_6_d_bild.gif]] [[Image:3_2_6_d_bildtext.gif]]
-

	The polar form is		The polar form is

-		+	{{Displayed math\|\|<math>2\sqrt{10}\Bigl( \cos\frac{\pi}{3} + i\sin\frac{\pi}{3} \Bigr)\,\textrm{.}</math>}}
-	<math>2\sqrt{10}\~~left~~( \cos \frac{\pi }{3}+i\sin \frac{\pi }{3} \~~right~~)</math>	+

Ian — Thu, 23 Oct 2008 10:30:19 GMT

← Nächstältere Version		Version vom 10:30, 23. Okt. 2008
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-	{{~~NAVCONTENT_START~~}}	+	We can determine the number's magnitude directly using the distance formula
-	~~<center> [[Image:3_2_6d.gif]] </center>~~	+
-	{{~~NAVCONTENT_STOP~~}}	+
		+	<math>\begin{align}
		+	& \left\| \sqrt{10}+\sqrt{30}i \right\|=\sqrt{\left( \sqrt{10} \right)^{2}+\left( \sqrt{30} \right)^{2}}=\sqrt{10+30} \\
		+	& =\sqrt{40}=\sqrt{4\centerdot 10}=2\sqrt{10} \\
		+	\end{align}</math>
		+
		+
		+	In addition, the number lies in the first quadrant and we can therefore determine the argument using simple trigonometry.


	[[Image:3_2_6_d_bild.gif]] [[Image:3_2_6_d_bildtext.gif]]		[[Image:3_2_6_d_bild.gif]] [[Image:3_2_6_d_bildtext.gif]]
		+
		+
		+	The polar form is
		+
		+
		+	<math>2\sqrt{10}\left( \cos \frac{\pi }{3}+i\sin \frac{\pi }{3} \right)</math>

Tekbot — Tue, 16 Sep 2008 15:02:01 GMT

← Nächstältere Version

Version vom 15:02, 16. Sep. 2008

Tekbot — Thu, 21 Aug 2008 08:10:44 GMT

Robot: Automated text replacement (-[[Bild: +[[Image:)

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Madde — Tue, 19 Aug 2008 16:13:45 GMT

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Oskar — Mon, 07 Apr 2008 12:18:28 GMT

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