Antwort 2.2:3 - Versionsgeschichte

Sekretariat1 um 11:38, 27. Aug. 2009

2009-08-27T11:38:18Z

← Nächstältere Version		Version vom 11:38, 27. Aug. 2009
Zeile 6:		Zeile 6:
	\|-		\|-
	\|c)		\|c)
-	\|width="50%"\| <math>\frac{1}{2}(\ln x)^2+C</math>	+	\|width="50%"\| <math>\frac{1}{2}\,\,(\ln x)^2+C</math>
	\|d)		\|d)
	\|width="50%"\| <math>\displaystyle\frac{1}{2}\ln\left(x^2+2x+2\right)+C</math>		\|width="50%"\| <math>\displaystyle\frac{1}{2}\ln\left(x^2+2x+2\right)+C</math>

Tekbot: Answer 2.2:3 moved to Antwort 2.2:3: Robot: moved page

2009-03-11T09:08:11Z

Answer 2.2:3 moved to Antwort 2.2:3: Robot: moved page

← Nächstältere Version

Version vom 09:08, 11. Mär. 2009

Tekbot: Svar 2.2:3 moved to Answer 2.2:3: Robot: moved page

2008-09-16T14:02:57Z

Svar 2.2:3 moved to Answer 2.2:3: Robot: moved page

← Nächstältere Version

Version vom 14:02, 16. Sep. 2008

Oskar: Ny sida: {| width="100%" cellspacing="10px" |a) |width="50%"| $-\cos x^2+C$ |b) |width="50%"| $\displaystyle\frac{\sin^2x}{2}+C$ |- |c) |width="50%"| $\frac{1}{2}(\ln x)^2+...$

2008-04-07T09:06:18Z

Ny sida: {| width="100%" cellspacing="10px" |a) |width="50%"|<math>-\cos x^2+C</math> |b) |width="50%"| <math>\displaystyle\frac{\sin^2x}{2}+C</math> |- |c) |width="50%"| <math>\frac{1}{2}(\ln x)^2+...

Neue Seite

{| width="100%" cellspacing="10px"
|a)
|width="50%"|<math>-\cos x^2+C</math>
|b)
|width="50%"| <math>\displaystyle\frac{\sin^2x}{2}+C</math>
|-
|c)
|width="50%"| <math>\frac{1}{2}(\ln x)^2+C</math>
|d)
|width="50%"| <math>\displaystyle\frac{1}{2}\ln\left(x^2+2x+2\right)+C</math>
|-
|e)
|width="50%"| <math>\displaystyle\frac{3}{2}\ln\left(x^2+1\right)+C</math>
|f)
|width="50%"| <math>-2\cos\sqrt{x}+C</math>
|}

Antwort 2.2:3 - Versionsgeschichte

Sekretariat1 um 11:38, 27. Aug. 2009

Tekbot: Answer 2.2:3 moved to Antwort 2.2:3: Robot: moved page

Tekbot: Svar 2.2:3 moved to Answer 2.2:3: Robot: moved page

Oskar: Ny sida: {| width="100%" cellspacing="10px" |a) |width="50%"|-\cos x^2+C |b) |width="50%"| \displaystyle\frac{\sin^2x}{2}+C |- |c) |width="50%"| \frac{1}{2}(\ln x)^2+...

Oskar: Ny sida: {| width="100%" cellspacing="10px" |a) |width="50%"| $-\cos x^2+C$ |b) |width="50%"| $\displaystyle\frac{\sin^2x}{2}+C$ |- |c) |width="50%"| $\frac{1}{2}(\ln x)^2+...$